Add Two Numbers | Live Coding with Explanation | Leetcode - 2

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This question uses the basic approach to add two numbers stores as nodes of linked list in O(Max(m,n)) time and space.

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AlgorithmsMadeEasy
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wow, u deserve 1milion views, what an explanation, thank you very much

nagasivakrishna
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Amazing video, keep up the great work! :)

ComputerScienceSimplified
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For line 24 & 25, can we have "if (p.NEXT != null) p = p.next" instead?

yanshanwan
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Your videos are really helpful...keep it going.

amlansarkar
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Very nicely explained, thank you, teacher<3

gokulnaathb
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carry = sum /10; -> 7/10 = 0.7;
why sum is saving -> sum %10 ??
any one know ?

worthyvibes
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Your carry = sum/10 will always return some value.. So your line number 28 will always have a value right.

pradeepgjain
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why carry is assigned to dummy??
carry=dummy; ??

divyaamohan
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class Solution {
public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
// write a code
ListNode dummy = new ListNode(0);
ListNode p = l1;
ListNode q = l2;
ListNode curr = dummy;
int carry = 0;

while(p!=null || q!=null)
{
int x = p!=null ? p.val : 0;
int y = q!=null ? q.val : 0;
int sum= x+y+carry;
carry=sum/10;
curr.next = new ListNode(sum%10);
curr=curr.next;

if(p!=null)
p=p.next;

if(q!=null)
q=q.next;
}
if(carry>0)
{
curr.next=new ListNode(carry);
}
return dummy.next;
}
}

/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/

shreeramkushwaha
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i beat 100% of the users, with 1ms runtime

vishalsupv