Solving Optimisation Problems, Perimeter, Area, Example - Calculus

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This calculus video covers a tutorial that may be useful for the AP, VCE, JEE, NEET, IB exams. It covers a worked example on solving optimisation problems using the derivative.
  1. DrOfEng
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Suppose the 3 sides were instead an open semi-circle? A 40 M half circumference could enclose 1600/pi sq-metres (approx 500). Of course the neighbours might not be too pleased (if he has any), and/or neighbouring plots wouldn't tesselate too well, but the yard would be a lot bigger!

fubblitious
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Double the y and obtain a recangle with x and 2y sides. Max area is for a square (well known) and this means x = 2y.
By the way, for max area of rectangle I have seen the russian teacher explaning that by a given perimeter of a rectangle (4a) one side is a + b and the other a - b, i.e. S = (a - b)*(a + b) = a^2 - b^2, i.e. if b = 0, then S is max.

plamenpenchev