Probability L-2 | ICSE Class 10 Maths Chapter 15 | Selina Solution | Umang | Vedantu 9 & 10 English

Probability | ICSE Class 10 Maths Chapter 15 | Selina Maths Class 10 | Umang Series | #Vedantu9thand10thEnglish with your favorite Gopal Sir. Probability Class 10 ICSE is one of the interesting sessions and it helps to get 100 marks in ICSE Class 10 Maths. In Vedantu, You can now watch today's session of Probability Class 10 ICSE | Probability Class 10 Vedantu | Probability Class 10 | Probability Chapter 15 | Class 10 Maths Chapter 15.

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The Vedantu online class will help you make a strategy to decode the concept, learn every detail of today’s topic Probability Class 10 ICSE | Probability Class 10 Exercise 15.1 | Probability Class 10 Introduction | Probability Class 10 Maths | Probability Class 10 Vedantu | Probability Class 10 | Probability Chapter 15 | Probability Vedantu | Probability Math | Probability | Class 10 Maths Probability | Class 10 Probability Chapter | ICSE Class 10 Probability | Class 10 Maths Chapter 15 | Class 10 Maths | Class 10 | ICSE Class 10 | ICSE.

➡️ Topics Covered in this Session:
♦ Probability ICSE Class 10 Maths
♦ Class 10 Probability
♦ ICSE Class 10 Maths Chapters
♦ Concise Mathematics Class 10
♦ Probability Class 10 Vedantu
♦ Selina Solution for Class 10 Mathematics

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[diyajain]

Make one shot whole chemistry video CBSE 10th plz

[findingmyself]

Waiting eagerly for the session✌✌🤩🤩🤩🤩🤩

[priyanshisingh]

Sir homework answer is p(birthday on different day)=364/365 and p(birthday on same day)=1/365

[sucharithalanka]

Sir I have a doubt in Q3 that you'vewritten 9 fav outcomes. can we try more than 9 like 10/85 or 14/85 so on... like trying more outcomes or less than 10 only please answer sir

[ritudubey]

Sir the solution to homework question should be
Q-1 (1) P(getting different birthdays) =364/365
(2) P(getting same birthdays) =1-P(getting different birthdays) =1-(364/365) =1/365