Top 10 Hardest Pure Questions 💀 [UPDATED] • A-Level Maths, Edexcel

This video contains questions from A-Level Edexcel Papers from 2018-2022.

0:00 How did I rank them?
3:26 Number 10
6:36 Number 9
9:57 Number 8
14:25 Number 7
18:47 Number 6
23:37 Number 5
26:20 Number 4
29:18 Number 3
33:51 Number 2
36:49 Number 1
39:03 Final thoughts

[theolawson]

Hi Mr Bicen, I was just wondering about question 9 (the differentiation question, part c specifically). What happens if 0<a<e^2? Surely the numerator and denominator are both going to be negative so it will become a positive value.

[zoey]

thank you for this video!! paper 1 is fast approaching now and this is really helpful

[ELS-egho]

You are the equivalent of Pep Guardiola tearing up the Premier League

[Vanced-xjlm]

Coming back to this video to brush up my maths skills after my gap year, very useful

[franciso-y]

I have my Year 12 mocks next week and unfortunately, they will be predicting University grades, so alongside exam questions on the online textbook, I have also attempted some AS papers. This is a really helpful video to remind me of topics I have forgotten to do, than you very much!

[GreyJaguar]

I found it very useful how you made the notes/workings out before the video and only focused on the talking/explaining them during the video :)

[aahad]

Hi Bicen, I commented before about A-Level Statistics (9ST0). Would love to see a walkthrough of papers from 2022 if you might have the time. Thank you!

[fixiecats]

its hard when bicen puts skull emoji in title lol

[christopherl]

I've already done my A levels in 2023. And this bring backs a lot of memories. Your videos helped me a lot. Especially a 100 days of Maths. I ended up with a B in the end where I ended up in 1st choice.

[rehama]

This video saved me for paper 1 maths today, absolute legend🔥

[kuba]

hey seb i passed into my 2nd year of uni doing engineering and even tho i didnt get the best grade i still passed. still remember the GOAT teacher and all your amazing videos. keep it going!

[jahanzaibullah]

Hi, love your content, been watching you for all of my year 1 maths, was wondering if you plan on doing content on MAT/TMUA exams

[krazmos]

Hi mr Bicen,
The videos for further pure 1 videos says I need to get a membership. Is it a bug or do I really need to pay to get help now?

[bonekichi]

hey mister bicen would you please sir make a video like this one for s1? i would really appreciate it since im performing it in this oct session (oct 12) . thank you in advance mister <3

[Exaltd]

Defo using this after I finish all the questions in the textbook LOLL

[idkidk]

Hi, regarding number 7's point of inflection section, I was taught that I could use the first derivative and input a value slightly smaller and slightly above the stationary point to show that the gradient is constant on both sides to prove it is a point of inflection. Would this way give you marks for this question. For example I mean subbing in root 28 and root 26 and showing there is no change in sign. Thanks

[reinelam]

Hi Mr Bicen, can you please also do one of these hardest question for statistics and mechanics? Thank you

[aguple]

9:21 For the second q part c, can’t you also say that a < e^2 ? (by making both the denominator and numerator negative)

[reemjaffar]

hello! I'm asking if the video includes all the pure papers or just P1 and P2?Also is this for the WMA12 and WMA11 paper reference, thanks in advance, I'm asking before watching the video to know before getting started

[mysteryguy]

Hello Mr Bicen, I think I have a method for question number 2, but it may be patchy so sorry if it's wrong. But basically, here's the proof:

If it's even, you can express it as 2k. (2k)^2 is 4k^2, and 1 less than this is 4k^2 -1. So 4k^2 itself obviously has a factor of 2k, and 4k^2 - 1 = (2k+1)(2k-1). So, for the square of an even number, OR the square of an even number minus one (which the question allows), you have 3 consecutive factors of (2k-1), 2k, and (2k+1). Every 3rd number must be a multiple of 3, so this is true for all even numbers.

Odd numbers can be expressed as (2k+1)^2. This is 4k^2 + 4k + 1, and 1 less than this is 4k^2 + 4k. Now 4k^2 + 4k + 1 obviously has a factor of (2k+1), but 4k^2 + 4k can be expressed as 2k(2k + 2). So, we've found factors of (2k), (2k+1), and (2k+2). So, by the same chain of reasoning for the even numbers, the statement must also be true for odd numbers.