Frequently Asked Java Program 06: Count Number Of Digits in A Number

Topic : Count Number Of Digits in A Number

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#DigitCount
#NumberDigits
#CountNumberDigits
#NumberLength
#DigitEnumeration
#NumericDigits
#DigitsInNumber
#CountingDigits
#NumeralCount
#NumberSize
#NumberLengthCheck
#DigitTally
#NumericMagnitude
#NumberLengthAnalysis
#NumeralQuantity
#DigitTotal
#CountingNumerals
#NumberLengthCalculation
#NumeralEnumeration
#NumberCharacteristics
#DigitPresence
#DigitQuantity
#NumericLength
#CountDigits
#NumberLengthInsight
#DigitCheck
#DigitQuantification
#NumericMagnitudeCheck
#NumberLengthAwareness
#NumeralTotal
#DigitObservation
#DigitAmount
#NumberStructure
#CountingNumerics
#NumeralQuantityCheck
#NumberMetric
#DigitCalculation
#NumericLengthAnalysis
#CountingCharacters
#NumberDigitness
#DigitAwareness
#NumberLengthEvaluation
#NumeralValue
#DigitInsight
#NumberCharacterization
#CountingNumberSymbols
#NumeralPresence
#NumberMagnitude
#DigitQuantitativeAnalysis
#NumericStructure

[r.rajalakshmi]

Sir we need your video specifically to reach how to debnug code.
1. Java program.
2. Rest api
3. On. different IDEs like Intellij

[mihirnarayan]

int num = 1234;
String s = "" + num;

[gauri]

You explain it the best way thanks a lot sir...

[akshaykathole]

Thank you so much sir because of you i am able to do coding.

[syedsaifahmed]

int len = (int) (Math.log10(num) + 1)

this is also a way to find the length in O(1) time complexity

[Mr_Raz_]

By converting to String

class HelloWorld {
public static void main(String[] args)

{
int num= 122345;
int length =
System.out.println(length);

}
}

[ananya]

Input to give multiple values
Ex: 12 24 4 3 78
In this value which is odd number and which place is odd number (mention palcement 4th is place is odd number) pls explain this method

[abhi]

How to count number of digits in a number starting with zero? For example if I enter a number 0123, the count output I must get is 4.

[pavankumar-brof]

public class CountDigits {
public static void main(String[] args) {
int N = 101;
Double d = new Double(Math.log10(N));
System.out.println( d.intValue() + 1);
}
}

[tsb_vlog]

At 6:47 count will be 6 . I think please check, you said it 5 again

[vyankateshodilwar]

In this programme if we give input number which is starting from 0 then it will not count that 0 because is condition is
while(num>0){
}

[mandardeshpande]

Hi Pavan sir in this program can we take in while condition as num!=0??

[ompa]

What to do when number entered starts from 0?
For eg - when number entered is 0123, count shows 3 instead of 4.
Kindly help.

[_abhi]

# Number of characters in a string
public class NumberOfCharacters {

public static void main(String[] args) {

String str = "Abhi";



}

}

[_nikhilyarnal]

what if n = 000;
the count will always be 0, but number of digits in n will be 3

[fahyiensher]

sir, how to sort string while ignoring Case
for eg input: Apple is Red
output : AeeilppRs

[HallOfMemeYT]

Can anyone try the input starting from 0, for eg. 0123, result showing count value to 3 instead of 4, if yes the program is incorrect, cause even if the input is starting from 0, the length should be given accurate by above program.Can You help me Sir, with regard to this.

[shaileshkumar.t]

can we just get the number as a string and use string.length() will it work?

[sajauddinmulani]

char[] chr =
System.out.println("Number of digits are "+chr.length);

[pavankumar-ihdw]

public class CountNumOfDigits {

public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter the number");
int num = sc.nextInt();

int count = 0;

for(int i=0; i<num; i++) {
if(num!=0) {
num = num/10;
count++;
}
}
System.out.println(count);
sc.close();
}
}

Sir, If I use for loop instead of while loop it is giving less number than a digit (eg: 1234 = 3).

Can you please provide me the solution for this?