A particle moving along x-axis has acceleration f, at time t given by...

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A particle moving along x-axis has acceleration f, at time t given by f = fo (1 - t/T), where fo and T are constants. The particle at t=0 has zero velocity. In the time interval between t=0 and the instant when f=0, the particle's velocity (vx) is
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During these three minutes of my life I thought a god from heaven come and taught me this quite complex question, thankyou so much and keep it up

khushimishra
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20. A particle is released from rest from a tower of height 3h The ratio of the intervals of time to cover three equal heights h is:

(1) t_{1}:t_{2}:t_{3}=3:2 :1

(2) 1:t_{2}:t_{3}=1:(\sqrt{3}-2)

(3 (4) t₁: 5:3 = 1: (√2-1): (√3-√2)

) t₁: : t_{3}=\sqrt{3}: √2:1.


Sir solve this ques also

prevoteck
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Clear explanation. Easily understandable. Thanks.

sankaralingamdurairaj
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awesomely explained sir.. hats off to teachers like you!

nikhilravikumar
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Thank you much sir for explaining in English love from kerala ❤️

nehmathnishanisha
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Sir you explain very well each line thank you.

sushmavikassahu
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But the ques is asking velocity between 0 to T so it means ques is asking v average then why every teacher is calculating instantaneous velocity please clear sir I am very confused

abhigamer
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1-t/T =0
t=T
howw plss explain mee🤔🤔

Saturo_gaming_
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Integration krte waqt niche 2 kese aaya

vinita
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Finally someone came with clean explanation🥲🥲

snehaa