IB Physics: Circuit Analysis

Explains the basic principals of circuit analysis including Kirchoff's Laws, and then illustrates the principals with several examples.
IB Physics Topic 5.2
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Many students have written to thank me for the success they had with their IB Physics exams and their IA or Extended Essay. Though the style is that of Khan Academy, the videos are more specific to the IB content, contain more simulations and interactive examples, and are performed by someone who has 25 years of experience teaching IB Physics, an MSc in Physics from a top University, and who was an NSERC scholar.
"I would just like to say a massive thank you to you for uploading your videos. I started the IB [and]decided to try HL Physics as it seemed interesting. It turned out to be very far from my forté and I was consistently getting 3s and 4s in tests and mock exams. So a few months before the exam period of this year, I began to panic...Then I discovered your channel. For four weeks prior to paper one, I virtually worshipped your videos, and worked along to them in my 'Big Book of Revision.' Last week, I received my results. Incredibly and almost unbelievably, I obtained a 6 in HL Physics. Not only that, but I was 3 marks off a 7."

[unesco]

the last two question showed up consecutively on my test last week. I love how the ib questions in ur vids come up on my exam

[snjn]

THE MOST HELPFUL PERSON ON THE INTERNETTTT

[sogandgolshahian]

Hello Mr. Doner. Firstly, I wanted to thank you for your incredible videos on the IB Physics syllabus. And secondly, I just had a quick question about the last IB question in your video at time 17:25. Since the resistances of all the resistors are the same, and Z and Y are part of one loop, wouldn't their potential differences be equal to each other? And the same question goes for X and Z, as they are also in one continuous loop? I am having a bit of trouble knowing when to use the loop rule, while the junction rule makes a little more sense to me. Answer B is talking about Y only, but you are talking about the equivalent resistance of X and Y in your video, which is why I am confused as to why the answer would be B and not C. Thank you for your time and for your help.

[hamza]

These videos are extremely helpful, thank you!

[julienh]

Hello Mr Doner,
At 10:50 you say that there is 6 ohms over 2 paths. Would there not be 12 ohms from the three resistors? Why is there only 6 when there are definitely 3 resistors that add up to a resistance of 12 ohms? I'm just a little confused about the math.

[shashankgarikipati]

Hello Mr. Doner,
why isn't the answer to the last question at 17:27 option C.

[leenkhasawneh]

Thank you for all your videos on here. I have one question regarding the calculations on 14:45: Wouldn't 1/25 +1/35 = 1/ 60 ~ 0.01667? And so R ~ 60 Ω?

[guanhantan]

Hello sir, for the question at 17:28, what if i use kirchoff law instead? So i=i1+i2. But since resistance of X and Y are the same so current i1=i2. So we can say that i1=i2=0.5i. When we add up the voltage of x and y, which is (0.5i×R)+(0.5i×R), we get i×R which is the same voltage as Z(i×R). So the answer should be C right?

[mohammedshukri]

Hello Mr. Doner. What would we do if two batteries were involved?

[spifuntastic]

13:46 for this question can't we also say that the voltage is 6V across the 2 ohm resistors cuz it's a continuous piece of wire?