exact value of sin(3 degrees)

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In this video, we will find the exact value of sin(3 degrees). We will see the special special triangles and the angle difference formula! ft. sin(15), sin(18), cos(15), cos(18)

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Mathematician:
Physicist: sin(3°)=pi/60
Engineer: sin(3°)=0

stewartzayat
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11:03 *thought download begins*
12:07 *thought download complete*

GreenMeansGOF
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this question is very easy using the fundamental theorem of engineering

*sin x ≈ x* | x in radians |
*π ≈ 3*
using these we get the
answer as 0.05
%error of 4.5%

hamiltonianpathondodecahed
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At 11:05 you can almost hear the cogwheels turning in his head...

DjVortex-w
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3:03 "Of course, 1 is equal to 2"
-BPRP 2019

alexharkler
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Bprp: *Runs math channel like a boss*

Also bprp: *1=2*

bruhmoment
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Really shows you even an expert has troubled moments

kennylim
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"1+1+1 =3"
We did it boys, an A in maths
👏👏👏

jeremyzamayla
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I work as a teacher of control systems which involves a lot of different math subjects. Thank you for showing HOW TO TEACH STUDENTS. I like how you tell in detail mathematics. I really appreciate it.

IoT_
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For sin and cos of 15° couldn't you have also used the difference formula for sin and cosine?
sin(45 - 30) = sin(45)cos(30) - cos(45)sin(30)
cos(45 - 30) = cos(45)cos(30) + sin(45)sin(30)

Periiapsis
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He teaches very friendly. Even for a simple calculation, he explains very kindly. So I can understand whole topic. Thank you for your works!

spinningcycloid
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"1 is equal to 2"
- bprp 2019

Btw. Great video

Mihau_desu
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Wohoo I'm not the only one deriving the angle sum from Euler's formula! My professor thought me mental xD. Didn't subtract points but asked me if I'm slightly troubled that I find that simpler than geometric proofs xD

Metalhammer
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Digging through some of my old papers, I found where I ran this calculation years ago . I just ran the half angle formula on 30 degrees to get the sin and cos of 15 degrees. I love your construction to do it geometrically - never seen that before.

patrickmckinley
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Nice problem! I have 2 comments:
1. 23:52 it's easier to just say "divide the hypotenuse by sqrt(2) to get the leg so it's sqrt(3)/sqrt(2)"
2. 24:44 the second leg should be sqrt(3)/sqrt(2) not sqrt(3)/sqrt(3) 😊

SyberMath
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I like how this went back to your old video about special phi triangles! Also, I loved how there's such an elegant way to find an exact sine of an angle! Great job on the video.

whyit
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The result should be almost equal to pi/60. For small angles, sin x approximates x with x in radians. Converting 3 degrees to radians is just multiply with pi/180.

sharmsma
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Can we do this without triangels
1]for 18°
For this equation sin(X)=cos(4X)
X=18° satisfies the eq where 4*18=72=90-18
We know cos(4X)=2cos^2(2X)-1
=2(1-sin^2(x))^2-1
Let y=sinx
Then y=1+8y^4-8y^2
8y^4-8y^2-y+1=0
This eq has 4 solutions but one of them is sin18
8y^2(y^2-1)-(y-1)=0
(y-1)(8y^2(y+1)-1)=0
y=1 is a sol but not sin 18 cuz sin90=1

8y^3+8y^2-1=0
8y^3+4y^2+4y^2-1=0
4y^2(2y+1) + (2y-1)(2y+1)=0
(2y+1)(4y^2+2y-1)=0
y=-0.5 is a sol but not sin18 cuz sin 210=-0.5

4y^2+2y-1=0
y=(-2±sqrt(16+4)) /(2*4)
=0.25(-1±sqrt(5))
Two solutions but we have one +ve solution and we know sin 18 is +ve

Then sin 18° =0.25(-1+sqrt(5))
Cos 18° =sqrt(1-sin^2 (18))
=sqrt(1-(6-2sqrt(5))/16)
=sqrt(5-sqrt(5))/2sqrt(2)

2]for 15°
Cos 30=2 cos^2(15)-1
Cos15=sqrt((1+sqrt(3)/2)/2)
=sqrt(4+2sqrt3)/2sqrt2
=sqrt(3+2sqrt3+1)/2sqrt2

=sqrt( (sqrt3+1)^2 ) /2sqrt2
=(sqrt3+1)/2sqrt2

Sin15=sqrt(1-cos^2(15))
=sqrt((1-sqrt(3)/2)/2)
=sqrt(4-2sqrt3)/2sqrt2
=sqrt(3-2sqrt3+1)/2sqrt2

=sqrt( (sqrt3-1)^2 ) /2sqrt2
=(sqrt3-1)/2sqrt2

3] finally sin 3°=sin (18°-15°)
=sin18°cos15°-cos18°sin 15°

hussiensayed
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I learnt a lot of special specials for the 1st time, though I knew sin (18) and sin (15) algebraically. Also the proofs of sin (a-b). Thank you, you are a special special teacher : )

jensonjoseph
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Super fun video :) I love how you talk about angles like they are people

bayanmehr