Russia Math Olympiad Question | You Should Know This

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🇷🇺 Russia | Math Olympiad Question | You Should Know This

🔍 Explore the intriguing world of Russian math Olympiad problems! In this video, we dive into a challenging math question that will test your problem-solving skills. Whether you're a math enthusiast or just curious about international math competitions, this is a must-watch.

🧠 Key Topics Covered:
📐 Understanding the Mathematical Concept
🇷🇺 Russian Math Olympiad Insights
🤔 Problem-Solving Strategies

🎓 Why Watch?
Unlock the secrets behind a thought-provoking math problem from Russia's renowned Olympiad. Enhance your problem-solving abilities and gain insights into the fascinating world of international math competitions.

👍 Who Is This For?
Math Enthusiasts
Students and Educators
Anyone Curious about Challenging Math Problems

📈 Timestamps:
00:00​ Problem
00:26 Step-by-Step Solution Walkthrough
05:04 Answer

👉 Don't forget to like, share, and subscribe for more captivating math challenges and educational content! Let's dive into the world of Russian Math Olympiad together. 🚀

#matholympiadquestion #RussianMath #ProblemSolving #matholympiadquestion #matholympiadpreparation #matholympiadproblem #olympiadmathematics #olympiad #olympiadpreparation
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Should have solved orally.
Area of Square - Area of Circle = Half the Area of White Part.
Now Double the Area of White part and subtract from Area of Square
= Area of Shaded Part

[16 - 2*(16 - 4π)] x^2 =

8(π-2) x^2

harshvardhansingh
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Deaw 2 diagonal line and divide each side by 2, then shaded area will divide into 8 equal parts.
In small square with s=2x, each shaded part has region is
A = 1/4 circle - isoscales triangle with s = 2x
A= (1/4 x π x r^2) - (1/2 x s x s)
A= (1/4 * π * (2x)^2) -(1/2 * 2x " 2x)
A = πx^2 - 2x^2 = (π-2)x^2

Then all shaded area is 8A = (8π-16)x^2 = 9.132x^2

sie_khoentjoeng
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I got the answer in my head before watching the video. I scroll to where the final answer is revealed and its a match.

Grassmpl
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I'm sorry, I'm a bit lost here.
Why didn't you take 1/8th of the diagram, apply the area of sector formula
A = ½ R^2 (Θ – sin(Θ))
A= ½ (2x)^2 (π/2 – 1)
A= x^2 (π – 2)
Then multiply by 8
A= 8 x^2 (π – 2)

Are you TRYING to make it look harder?

kimba
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This questions is in my high school textbook

shauryasingh