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The momentum, the average force and impulse in the movement of the ball
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A ball of mass m=8.0∙10^(-2) kg starts from rest and falls vertically downward from a height of 3.0 m. After colliding with the ground, it bounces up to a height of 2.0 m. The collision takes place over a time interval of ∆t=5.0∙10^(-3) s. Calculate:
1) the momentum of the ball immediately before and immediately after the collision
2) average force exerted by the ground on the ball
3) impulse imparted to the ball
1) the momentum of the ball immediately before and immediately after the collision
2) average force exerted by the ground on the ball
3) impulse imparted to the ball
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