Supremum and Infimum

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Very very helpful explanation. After struggling 2 days finally I got the idea of the proof of general definition of supremum and infimum. Dear sir, Thank you from the button of my heart

RtGMUmEaRKING

One question on the definition of Supremum. Say there is a set S = [1, 4] and I take a = 3. So as per the definition given above. for all e>0, there exist (!) an x in S s.t. a-e < x <= a. So then 3 is a Supremum of [1, 4]. Which is definitely not the case. I guess we have to say for any upperbound a of set S, not just any element a...

somnathkundu

Fabulous
Very well elaborated made very easy to get about Infima and Suprema
Thanks a lot

VikasKumar-eetm

Nicely explained! Better than my teacher at IIT Kgp and understandable enough for a student on his first day!

SohamChakraborty

Nothing is interesting than proving theorems in real analysis 😁 I am in love with sk mapa though I am bsc general student.

lifegame

Excellent, I understand this clearly now, Im now familiar on the terms they used.

wevenlabesig

Thank you so much sir for such a clear explanation

vaishnavinair

Key concepts explained so well. Donnyavad!

punditgi

I have never seen real mathematice teaching like you

ramanujanclasses

Really good explanation, could I get the notes with the other proof for f(c)>0 but I don't know if it's actually correct. I followed your same steps but going from the right to the left. Thank you in advance

Albkiller

i have one doubt this topic, upper bound is also a lub, lower bound is take it as g l b

bhavyavenkataramua.v

very nice.send more and more in my mail

shyamalmanna

I like your lecture sir I want your notes so can you please give me any link to download it

sonukumar-

B + epsilon can't be lower bound
A - epsilon can't be upper bound
Max min must be elements of the set
Super inf may not be elements of the set
Prove intermediate value theorem using supremum infimum
Book spewak

alute

sir, i think their should be 1 - e < x < 1 + e. for x being the lub.

deepdhiman

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