Algebra 5 - Symmetric Difference

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The symmetric difference of two sets is the collection of elements which are members of either set but not both - in other words, the union of the sets excluding their intersection. Forming the symmetric difference of two sets is simple, but forming the symmetric difference of three sets is a bit trickier.
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What a beautifully presented tutorial. Thank you for the hard work.

Kayotesden
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Your series helped me tremendously. This is the best way of storytelling and math, effective, animated and fun to watch. Many compliments on your work.

MarcoMeerman
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THIS IS THE ONLY BEST CLASS IN MATHS, I HAVE EVER WATCHED. THANK YOU SIR

rajeshchandrasekharan
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I wish if only I had gotten this high quality education during my primal am a big fan of your work.

kapilpanchal
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This is absolutely brilliantly explained

dvcadigital
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Basically the previous set is anything that doesn't overlap A and B. If there was a commonality between A and B that was also in C, it can be included in the symmetric difference between the first set and C because the first symmetric difference will have eliminated that commonality.

basedonprinciple
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I'm a bit confused by the area where all three circles intersect. In this example, the intersection was a 4. Why is 4 a part of the symmetric difference if it is in circle "a", circle "b", and circle "c"?

SheaStott
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idk about anyone else but the fact that set C was not {2, 4, 6, 8} just killed me

ximbabwe
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amazing! i loved it. thanks! it helps me a lot. i enjoyed the animation. i hope you'd also make videos such these on topics of geometry( Basic Geometry, Angles, Basic Constructions, polygons, triangles and quadrilaterals).

markramonrodriguez
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Great! videos now i can now comprehend math, now i luv math than hate it, thanks for the incredible effort you made, its pretty quite useful for me, i luv the toon stuff also its a awesome combination, . i hope many out there will find math interesting and beautifully elegant.

pedrolaonglaan
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En el diagrama de Venn se observa que no se puede excluir a priori la intersección de los tres conjuntos A∆B∆C como se hace con dos conjuntos. Primero debe ser definido el par A∆B, (que tambien puede ser B∆C) y de esta manera tenemos a un nuevo conjunto que se intersecta con C y como se tiene un vacio en el medio no hay nada que intersectar con C, entonces este último conjunto devuelve el espacio que se había quitado anteriormente

fraylauri
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Brilliant, so interesting, thank you

deqnskiable
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wow awesome very clear and apt way of explaining so nice to explain the kids who r average students even a lay person can understand thk u so much for uploadinng

vandana
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Great explanation. Thanks for uploading.

abrarrahman
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I wish Professor Von Shmohawk was my discrete math teacher

BootlegBoomerangs
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Wait a minute. With that particular diagram, isn't 4 in an intersection, in fact, the intersection of all three circles? Wouldn't that therefore be left out of the complement?

KBAFourthtime
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Would you please tell me, By which software did you create this animation?

hmishak
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So, even the 4 would be included? I thought it wouldn't be. So, symmetric difference is elements that are shared between all sets, as well as elements that are exclusive to it's own set. I think I got it now.

ChristopherGast-ds
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Sir (A∆B) ∆C=A∆(B∆C) please proved in 'set bilder form'

pradeepnaik
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That was absolutely perfect, thank u very much

amlhassan