Graphing Instantaneous Power

An 8.53 kg pumpkin is dropped from a height of 8.91 m. Will the graph of instantaneous power delivered by the force of gravity as a function of _____ be linear? If not, what would you change to make the graph linear? (a) Time, (b) Position.

0:00 Intro
0:12 The example
1:08 The equation for instantaneous power
1:43 Part (a): Solving for velocity as a function of time
2:55 Part (a): Solving for power as a function of time
3:23 Part (a): Is power as a function of time linear?
4:26 Part (a): Graphing power as a function of time
5:03 Part (b): Solving for velocity as a function of position
5:58 Part (b): Solving for power as a function of position
7:02 Part (b): Is power as a function of position linear?
7:38 Part (b): How can we make the graph linear?
8:33 Part (b): Graphing power squared as a function of position

Next Video: Average Power Delivered by a Car Engine - Example Problem

Multilingual? Please help translate Flipping Physics videos!

Previous Video: Average and Instantaneous Power Example

Please support me on Patreon!

[BanValsimot]

Wait....regarding the power vs position....for "g" we write -g but for yf we write +y in equation...should not we write: P=m*g*square(-2g * -yf) and have a positive slope in the end?

[Anveshkrishna]

Mr. P I have a question
Why don't we use the equation Power = Work divided by time and make Work equal to the Force due to gravity times the displacement times the cosine of the angle between the force and displacement? We would see that as time increases, the displacement increases, but I don't know if that graph would be linear. Or is this wrong because my equation contains both displacement and time? Please clear my confusion.

[KoalaKing]

Y'all need some sound foam in that room

[Anveshkrishna]

Also why is the instantaneous velocity the final velocity? I umderstand that final velocity is in fact an instantaneous velocoty but why do we specifically use velocity final?