If x^2+1 Divides (P(x))^2, Then It Also Divides P(x) [Polynomial Week #3]

Today I am going to conclude the "Polynomial Week" series by presenting one proof related to polynomial division. If x^2+1 divides polynomial (P(x))^2, can you prove that x^2+1 also divides polynomial P(x)?

And of course, since this problem is also related to polynomial division, we are going to use the famous property related to division: In this video it is stated as a = bq + r.

[More Polynomial-Related Problems]
- A Cubic Polynomial with 4 Values Given, Solved Judiciously
- The Polynomial Division and Remainder Problem

#Algebra #Polynomials #Proofs #PolynomialDivision

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