Calculus I: Critical points and Extrema

preview_player
Показать описание
In this video, we discuss what critical numbers are and how to use them to determine extrema around a closed interval.

00:00 - Introduction
00:45 - Definition of a critical number
02:02 - Example 1
05:36 - Method for finding extrema in a closed interval
08:20 - Example 2
11:27 - Example 3
14:40 - Example 4
  1. Math for Thought
  2. Calculus
  3. Intro calc
  4. introductory calculus
  5. Calculus I
  6. MATH 100
Рекомендации по теме
Critical points introduction 0:07:53

Critical points introduction | AP Calculus AB | Khan Academy

Finding Critical Numbers 0:21:19

Finding Critical Numbers

Local Extrema, Critical 0:14:35

Local Extrema, Critical Points, & Saddle Points of Multivariable Functions - Calculus 3

critical points of 0:05:25

critical points of multivariable functions (KristaKingMath)

Applications of Derivatives 0:08:57

Applications of Derivatives | Critical Points

Finding critical points 0:05:51

Finding critical points | Using derivatives to analyze functions | AP Calculus AB | Khan Academy

Calculus AB/BC – 0:14:50

Calculus AB/BC – 5.2 Extreme Value Theorem, Global Versus Local Extrema, and Critical Points

Critical Points, Increasing 0:10:50

Critical Points, Increasing and Decreasing, Local Extrema Example with Rational Function

Calculus 2: Solving 0:51:52

Calculus 2: Solving Exam 3 -All things SEQUENCES & SERIES! -Fall 2019 Part 2| Math with Profess...

Find critical points 0:03:30

Find critical points of a polynomial

Critical Points from 0:01:50

Critical Points from a Graph

How to find 0:25:26

How to find Critical Numbers (Worked Examples)

Calculus 1 Lecture 1:34:07

Calculus 1 Lecture 3.1: Increasing/Decreasing and Concavity of Functions

Finding Local Maxima 0:06:17

Finding Local Maxima and Minima by Differentiation

How to Find 0:21:30

How to Find Critical Values/Critical Numbers (Calculus 1) | Math with Professor V

Q12 p179 Find 0:09:04

Q12 p179 Find Critical Points Local Maximum Minimum Neither First Derivative Test MCV4U

Oxford Calculus: Finding 0:12:17

Oxford Calculus: Finding Critical Points for Functions of Two Variables

Finding the Critical 0:05:00

Finding the Critical Points of a Function

Finding Absolute Maximum 0:17:17

Finding Absolute Maximum and Minimum Values - Absolute Extrema

Critical Points and 0:06:36

Critical Points and Extrema (Intro & Examples)

Critical points + 0:07:17

Critical points + 2nd derivative test: Multivariable calculus

Inflection point grade 0:00:30

Inflection point grade 12

Calculus - Critical 0:10:33

Calculus - Critical Points and Derivatives using Quotient Rule

Find and Classify 0:09:49

Find and Classify all Critical Points of a Multivariable Function

Комментарии
Автор

Hey Cloudy. I could be very confused, but why in your last example the absolute minimum (9/8, 51/4) and not (-7, 12)? My thought is that 12 < 12.75 so that one is the absolute minimum.

emmavandeventer
Автор

In example 4 why didn’t we consider a case where f-1(x) is u defined I.e. denominator of differentiated function is 0

NaziaTarannum-ss
Автор

Hey man is it possible to a replace the absolute value of |x| with square root of x^2 and then do the derivative for the last question?

ghassanebrabish