Problems on Ages _ LESSON #2(Twice/Thrice Age)

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Timestamps:
0:00 Two Important Note
3:04 Question-1
5:20 Question-2
8:50 Question-3
11:25 Question-4
15:44 Question-5
19:43 Question-6
23:19 Question-7
26:07 Question-8
28:34 Question-9
31:01 Question-10
34:24 Question-11

**********Problems On Ages(All Lessons***********

LESSON-1 : Intro+Basic Questions

Lesson-2: Twice/Thrice Age

Lesson-3: AVERAGE AGE

Lesson-4: Doubt Session

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[badsheshakhilkumar]

Sir in question number 6 the first equation is A+C+2B, and thank u very much sir, iam getting all sums 👍 Iam very happy with this and your slowly, steady explanation is awesome sir, thank u very much sir

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[sarangabalanparthipan]

Question 8 can be solved more easily.
(X -5)(Y-5) = 4(Y-5)
Cancel (y-5) both the side.
X-5 = 4
X = 9
Y = 45 -9 = 36

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[aksharasri]

Thanks for the awesome lecture sir!
On question 6, twice the age of B, will be the equation A+C+2B = 59.

[ashwathisriram]

In qus.no 6: 1st equation is
A+C+2B=59 sir.

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From TELANGANA

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