How to Copy Selected Properties from One Object to Another in TypeScript Using .map()

Discover how to efficiently copy specific properties from one object to another in TypeScript with the powerful `.map()` method while ensuring optimal code readability and functionality.
---

Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: Copy properties using .map() typescript

If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com.
---
How to Copy Selected Properties from One Object to Another in TypeScript Using .map()

When working with arrays of objects in JavaScript or TypeScript, there often arises the need to copy properties from one object to another based on some condition. This can become confusing, especially when attempting to do so in a single step. In this post, we will explore how to effectively and efficiently copy selected properties using the .map() method in TypeScript.

The Problem

Imagine you have two arrays of objects:

An array abc containing personal information.

An array xyz with additional details like weight, height, and mobile number.

Example Data

Here's a look at our sample data:

[[See Video to Reveal this Text or Code Snippet]]

The task is to copy the height and mobile properties from xyz to abc, based on matching id properties. If we attempt to do this in a single step, we might end up with confusing results.

The Solution

Instead of trying to copy properties in a singular line, let's break it down into clear steps using the .map() method. Here’s the refined code that accomplishes this:

[[See Video to Reveal this Text or Code Snippet]]

Breakdown of the Solution

Using .map(): We are using .map() to iterate over each object in the abc array. This method allows us to transform each object into a new object based on our criteria.

Destructuring Properties: By using destructuring, we extract the height and mobile values from the found object. The || {} ensures that we do not run into undefined errors if there’s no match.

Merging Objects: Finally, the spread operator (...) is used to merge the properties of the original object x with the newly extracted height and mobile values.

Result

When you execute the above code, you'll receive a new array result that contains all properties from abc plus the height and mobile properties from xyz:

[[See Video to Reveal this Text or Code Snippet]]

Conclusion

Using the .map() function in combination with destructuring and finding matches, we can effectively copy specific properties from one array of objects to another in TypeScript. This approach enhances code readability and maintainability while achieving the desired outcome. Mastering such techniques can greatly influence your efficiency as a developer!

Happy coding!