Solving Quadratic Equations By Factoring - SAT Math Part 2

This is part 2 of the SAT Math video series which focuses on solving quadratic equations by factoring by using the quadratic formula.

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How To Factor Trinomials:

The Greatest Common Factor:

Difference of Squares & Sum of Cubes:

Factoring Perfect Square Trinomials:

How To Factor By Grouping:

Cubic Polynomials:

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Solving Quadratic Equations By Factoring:

Quadratic Equations Completing The Square:

How To Factor Difficult Quadratic Equations:

Hard Factoring Examples:

Factor Completely - Multiple Variables:

Factoring Higher Degree Polynomials:

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Factoring Trinomials With Large Numbers:

Factor Trinomials With Negative Exponents:

Factoring - Rational Exponents:

Factor Theorem and Synthetic Division:

Finding All The Zeros of a Polynomial:

Real and Imaginary Solutions:

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Final Exams and Video Playlists:

Full-Length Videos and Worksheets:

[clfzscc]

This guy literally does everything but organic chemistry 😂. His Physics videos are amazing

[rawankarim]

You’re a big reason I’m getting better in physics and chemistry and now you’re the reason the reason I’m more optimistic about my upcoming SAT

[yinxiaowang]

I was talented in math, however by staying at home attending online school for 1 year I forgot almost everything of math in 9th and 10 the grade. But now I reviewing all of it by this, doing well. THX !!!

[alsinan]

for question 12 instead of doing all that work just remember that the sume is -b/a and the prod are c/a

[nikolaninkov]

For Q12: Organic Chemistry tutor made a mistake, -9 + 8 equals -1, not 1. Also, all this calculating can be avoided by using viette's theorem, which states that for every quadratic equation with solutions x1 and x2, x1 + x2 = -b/a and x1x2 = c/a. Hope this helps!

[gulde]

Easier method for Q2 is

Sum of solutions = -b/a
Product = c/a
And thats only for quadratic equations

[beyza]

For Q12
6k^2+k-12
( 3k -4)
(2k 3)
we multiple diagonally and then
we will find this: 9k-8k=k so this solution is median number in this equation. Finally, we are writing this two factor side by side.
this means (3k-4)(2k+3) and we are equalizing 0. And we will find k= 4\3 and k=-3\2
ps., 3k*2k=6k^2 and (-4)*3=-12

[ZIKORILK]

in Q.11.
you can build an equation in the forme a^2+2ab+b^2 by that: 51=x^2+8x+3,
here we have a=x & b=8/2=4
then we need to make 4^2 or 16 to make it more clear, 3=16-13,
so the equation will be like this:
51=x^2+8x+3
=> 51=x^2+8x+16-13
=> 51+13=x^2+2*4*x+4^2
=> 64=(x+4)^2
=> (x+4)^2-64=0
=> (x+4)^2-8^2=0 ; we knows that: a^2-b^2=(a-b)(a+b)
=> [(x+4)-8][(x+4)+8]=0 ; we knows that:a*b=0 is mean that a=0 or b=0
=> x+4-8=0 or x+4+8=0
=> x-4=0 or x+12=0
=> x=4 or x=-12
but in the answers we have just 4 so answer is D, thanks for everything <3

[saki]

Whenever you increase the number of videos that you upload into your chennel, the number of subscribers goes up.

[stephinehab]

For number twelve there is simple rule for solving which is -b/a . In that question b=1 and a=6 so it is -1/6 .

[gkwise]

Can't wait to get a perfect score with u.

[agrimaag]

Q.13
factorize 116
2 X 2 X 29 which can be written as 2 X 29^1/2

[pranavr]

Hello sir. First off all wanted to appreciate you giving out free education. wanted to suggest you a couple short tricks. Like Q12 could have been solved in a second, as the sum of the roots of 'Ax^2 + Bx + C' is '-B/A'

[kezia]

In the near future i hope to have an amazing lecturer as you.

[Spidermanlover]

Factoring is really difficult for me. I’ve done pretty decently in all the math leading up to factoring, but this is like my Achilles heel

[sailor]

12. 6k²+1k-12 = k²+(k/6)-(12/6)
You can read the answer by just looking at the b term.

[sokh]

To solve Any quadratic equations-
ax²+bx+c
-b±√b² - 4ac/2a

[lyliah]

you do this solving method when there is only Quadratic Equations yeah?( asking for the first question, and sorry for bad english)

[Mohammed-bfs]

there is a much faster way to solve the second question.tThe sum of solutions can be found using this -b/a

[qixry]

i got a question why is question 11 after he factored he replaced the whole thing with the factor he got and got two solutions for that
but in question 12 he factored but only replaced the middle term with the factored numbers he got, i dont get it