Straight Lines | One Shot | #BounceBack Series | JEE Maths | Unacademy Atoms | Nishant Vora

Complete Straight Lines will be discussed in this session for JEE Mains by Nishant Vora.

Use Special Code: "NVLIVE" (To avail Maximum DISCOUNT)

In this JEE 2022 session, Nishant Vora Sir will be discussing Determinants in One-Shot for JEE Main & Advanced 2022. Here, Nishant Vora Sir solves various examples based on the topic of Determinants for JEE Main & Advanced 2022. Nishant Vora Sir also shares his various preparation strategies which will help you to crack the JEE Main/NEET Exam. Watch This video to know all about Determinants.

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00:00 - Introduction
07:09 - Minor & Cofactor
32:51 - Shortcut to find Value of determinant
38:12 - Properties of Determinants
02:17:10 - Special Determinants
03:07:26 - Method to Solve System of linear Equations
03:09:13 - Cramer's Rule
03:21:03 - Cramer's Rule (For Homogenous Equation)
03:25:55 - Gauss - Jordan Method
03:30:47 - Questions
04:26:49 - How to differentiate a determinant ?
04:41:35 - Cayley - Hamilton Theorem

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[omdapke]

DO LIKE THE COMMENT IF I HELPED YOU!
LECT STARTS AT 10:00
AREA OF TRIANGLE 22:05
AREA OF QUADR. 26:20
SLOPE OF LINE 34:51
iNTERCEPTS 34:30
EQUATIONS OF STRAIGHT LINES 52:32
Normal/ perpendicular form 01:08:05
Angle between 2 straight lines 01:31:18
5 Imp things about triangles 2:23:54
locus of point 3:09:36
Lenght of perpendicular 3:24:35
Parametric eqn of straight line 3:45:34
Position of point wrt to line 3:53:43
Concurrency of 3 lines 4:00:48
Family of st lines 4:07:11
Optics based questions 4:45:20
Pair of st lines 5:22:09
Homogenisation 5:44:00

[S_S_]

16:08 (pyq)
18:53(pyq)
31:21(pyq)
47:02(collinearity check by determinant method)
49:01
1:17:25(imp note for normal form of line is that:P ka value hmesha +ve hi hoga, since P is distance. So we have to adjust theta according to it)
1:20:13(pyq)
1:24:02(pyq, bisceting, we can use mid pt formula)
1:27:42(pyq)
1:50:54(PYQ)
2:28:40(key step to find circumcentre)
2:38:04(finding orthocentre)
2:44:02(spcl case:right triangle)
2:46:21(case of equilateral triangle)
2:49:23(ortho, centroid, circumcentre are collinear and ratio wala cheez hmesha right angle triangle se yaad rkhna)
2:50:50(pyq)
2:56:449(pyq)
3:01:26[pyq, isme as circumcentre is also the origin, thus assume points as (Rcosa, Rsina) (Rcosb, Rsinb)and (Rcosy, Rsiny) kuki sbhi centre se R hi ke distance pe honge]
3:10:40(Working rule for finding Locus)
3:14:18
3:18:00(Imp case of A stick lying against coord axes: The middle pt of stick moves in a circle, with radius =Length of stick/2)
3:29:40(pyq)
3:34:49(adv, 20)
3:45:30(Parametric form of St line, kab aur kese lagate h)
3:49:18(pyq on Parametric form of St line)
3:57:39(pyq)
4:02:02(condition for concurrency of 3 lines)
4:03:13
4:07:47(fam of St line ka eqn tbhi lagana, jab ek line ka eqn pche, jo intersection of L1 and L2 se pass krrha hoga)
4:18:02(fam of St line de dia ho, to wha se eqn ko split krke L1 and L2 split krnaa ana chahiye)
4:40:35(if coeff of eq of fam of line are in AP, then finding fix pt)
4:43:43(pyq)
4:51:43[img of pt (a, b) abt the line y=x is (b, a)]
4:52:23(reflecting line problems)
4:55:03(pyq)
4:59:27(adv, 19)
5:11:46(problem on angle bisector of two lines)
5:14:36(after making constants+ve...jo bhi a1a2 + b1b2 ka sign milega, whi sign hoga obtuse bisector ka)
5:16:04(working rule for bisctor containing origin: just make constant+ve & +ve sign wla hmesha containing origin)
5:19:09(if a1a2 +b1b2=0, then both are perpendicular angle bisector)
5:29:52[pair of St line passing thru origin have eqn: ax²+2hxy +by²=0 and h²-ab≥0(discriminant≥0)]
5:31:52(way to solve eqn of pair of St line passing thru origin, just put y=mx)
5:36:49(spcl cases for pair of St lines), 5:44:35(homogenisation : kab aur kese lgaenge)
5:46:48(eg of homogenisation)
5:57:30(adv, 21)

[stable]

18:53(pyq), 31:21(pyq), 47:02(collinearity check by determinant method), 49:01, 1:17:25(imp note for normal form of line is that: P ka value hmesha +ve hi hoga, since P is distance. So we have to adjust theta according to it), 1:20:13(pyq), 1:24:02(pyq, bisceting, we can use mid pt formula)1:27:42(pyq), 1:50:54(PYQ), 2:28:40(key step to find circumcentre), 2:38:04(finding orthocentre), 2:44:02(spcl case:right triangle), 2:46:21(case of equilateral triangle), 2:49:23(ortho, centroid, circumcentre are collinear and ratio wala cheez hmesha right angle triangle se yaad rkhna), 2:50:50(pyq), 2:56:449(pyq), 3:01:26[pyq, isme as circumcentre is also the origin, thus assume points as (Rcosa, Rsina) (Rcosb, Rsinb)and (Rcosy, Rsiny) kuki sbhi centre se R hi ke distance pe honge], 3:10:40(Working rule for finding Locus), 3:14:18, 3:18:00(Imp case of A stick lying against coord axes: The middle pt of stick moves in a circle, with radius =Length of stick/2), 3:29:40(pyq), 3:34:49(adv, 20), 3:45:30(Parametric form of St line, kab aur kese lagate h), 3:49:18(pyq on Parametric form of St line), 3:57:39(pyq), 4:02:02(condition for concurrency of 3 lines), 4:03:13, 4:07:47(fam of St line ka eqn tbhi lagana, jab ek line ka eqn pche, jo intersection of L1 and L2 se pass krrha hoga), 4:18:02(fam of St line de dia ho, to wha se eqn ko split krke L1 and L2 split krnaa ana chahiye), 4:40:35(if coeff of eq of fam of line are in AP, then finding fix pt), 4:43:43(pyq), 4:51:43[img of pt (a, b) abt the line y=x is (b, a)], 4:52:23(reflecting line problems), 4:55:03(pyq), 4:59:27(adv, 19), 5:11:46(problem on angle bisector of two lines), 5:14:36(after making constants+ve...jo bhi a1a2 + b1b2 ka sign milega, whi sign hoga obtuse bisector ka), 5:16:04(working rule for bisctor containing origin: just make constant+ve & +ve sign wla hmesha containing origin), 5:19:09(if a1a2 +b1b2=0, then both are perpendicular angle bisector), 5:29:52[pair of St line passing thru origin have eqn: ax²+2hxy +by²=0 and h²-ab≥0(discriminant≥0)], 5:31:52(way to solve eqn of pair of St line passing thru origin, just put y=mx), 5:36:49(spcl cases for pair of St lines), 5:44:35(homogenisation : kab aur kese lgaenge), 5:46:48(eg of homogenisation), 5:57:30(adv, 21)

[AnmolSah]

Sir aapne Diwali ke din bhi class liya yeh batata hai aapka aur mam ka dedication god gifted hai

[Depressed_JEE_Aspirant.]

Introduction 9:41
Cartesian coordinate system 09:41
Distance formula 12:30
Section formula 14:25
Area of triangle 22:10
Area of quad 26:30
Slope of line 34:46
Intercept 38:30
Collinearity of three points 46:28
Equation of straight line in various forms 52:28
Angle between two straight lines 1:31:17
Break 1:57:54
5 IMP point on triangle 2:23:03
Special cases 2:43:22
Locus of a point 3:09:18
Length of perpendicular 2:23:41
Distance between 2 parallel line 3:28:02
Parametric equation of straight line 3:44:26
Position of point wrt straight line 3:55:35
Concurency of 3 lines 4:00:43
Family of straight lines 4:07:05
Break 4:22:10
Optics based problems 4:45:17
Equation of angle bisector 5:05:15
Homogenation 5:43:48
THE END 6:08:22

[KRISHNAGUPTA-zzvy]

Sir Kitni baar dil jitoge, ek hi dil ha humara ...❤️❤️
Taking class even on Festival .Hats off too Your dedication sir..💯☺️

[EmptyyCups]

Diwali ke din bhi 6 hr+ class...
I have No words to describe ur DEDICATION LEVEL.
Hats off 🔥

[ujjwalfromjharkhand]

1)34:55 slope of a line
2)38:33 intercept
3)46:52 collinearity of three points
4)52:38 equation of st line in various form
i)53:44 point slope form
ii)55:13 two point form
iv)59:45 intercept form
v) normal form 1:08:13

[namanraikwar]

sir's dedication level is infinity

[amritbanjade]

He is explaining so smoothly, Thank you sir . Love from Nepal 🇳🇵

[playerlegit]

Concise and appropriate.
Except this just do "excenter, transformation of cartesian and polar coordinates, shifting of origin and rotation of axis "

[kartavyax-a]

Introduction 9:41
Cartesian coordinate system 09:41
Distance formula 12:30
Section formula 14:25
Area of triangle 22:10
Area of quad 26:30
Slope of line 34:46
Intercept 38:30
Collinearity of three points 46:28
Equation of straight line in various forms 52:28
Angle between two straight lines 1:31:17
Break 1:57:54
5 IMP point on triangle 2:23:03
Special cases 2:43:22
Locus of a point 3:09:18
Length of perpendicular 3:23:41
Distance between 2 parallel line 3:28:02
Parametric equation of straight line 3:44:26
Position of point wrt straight line 3:55:35
Concurency of 3 lines 4:00:43
Family of straight lines 4:07:05
Break 4:22:10
Optics based problems 4:45:17
Equation of angle bisector 5:05:15
Homogenation 5:43:48
THE END 6:08:22

[Pranali]

At 1:30:50 your answer and option is not matching because there we have to take angle between normal and x+y=0 as 60° from other side. Then angle between normal and X-axis will become 75°. And we will get option 4.

[sahab]

I STUDY IN FIITJEE, AND LITERALLY I HAVE UNDERSTOOD THIS TOPIC ONLY FROM YOU DEAR SIR, YOU R D BEST❤️

[trivedishorts]

Break 1:58:20
Start 2:23:20
Break 2 - 4:23:00
Start 4:39:19

[tomandjerry]

The only man who can can help you with maths at the last moment

[atulkumar]

Ye unacademy walon ne timestamps bidi pi kar lagai h kya

[barkhaaa.]

Can't thank youu enough sir!! THANKYOUU FOR EVERYTHING YOU DO FOR US. You deserve the world sir! Thankyouu😭❤️

[abhishekiistian]

Introduction 9:41 -- --
Cartesian coordinate system 9:41 18:53 31:21
Distance formula 12:30 47:02 49:01
Section
Area of
Area of quad 26:30 1:50:54 2:28:40
Slope of line 34:46 2:38:04 2:44:02

Collinearity of three points 46:28 2:50:50 2:56:49
Equation of straight line in various forms 52:28 3:01:26 3:10:40
Angle between two straight
Locus of a
Length of
Distance between 2 parallel line 3:28:02 3:57:39 4:02:02
Parametric equation of straight line 3:44:26 4:03:13 4:07:47
Position of point wrt straight line 3:55:35 4:18:02 4:40:35
Concurency of 3
Family of straight
Optics based problems
Foot of perpendicular or image of point 4:45:17
Reflection problems 4:53:02
Equcation of angle bisector 5:05:14
angle of bisector of acute and obtuse - 5:10:58
5:11:46 5:14:36
Equation of angle bisector 5:05:15
ange bisector of containing origin and not containing origin 5:16:00
pyq 5:19:09
5:22:06 pair of straight line
5:34:18 angle of pair of straight line
though origin
5:39:05bisector of the line represented by ' ax^2+2hxy+by^2 = 0



THE

[parthkarma]

Sir i was going offline ccg for last 3-4 months ; but belv me what i have understood in this 6hr session is more than in coaching apart from doubt solving✨✨