Straight Lines Class 11 | One Shot | JEE Main & Advanced | Arvind Kalia Sir

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Best Straight Lines One shot session for JEE by Arvind Kalia Sir
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Welcome to an immersive learning experience that demystifies the complexities of "Straight Lines" for Class 11 students gearing up for JEE Main & Advanced. Guided by the expertise of Arvind Kalia Sir, this meticulously crafted tutorial offers a unique "One Shot" opportunity to conquer this fundamental topic.

Arvind Kalia Sir, a revered educator known for his passion and proficiency, takes you on a transformative mathematical journey. This comprehensive session covers the essence of straight lines, from equations to slopes, intercepts, and beyond. With a focus on clarity and efficiency, this tutorial optimizes your learning process, making it an indispensable resource.
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#jeemain2024 #jeeadvanced #straightline #mathematics #maths #iitjee #exampreparation #competitiveexams #problemsolving #ExamTips #jeemain2025 #previousyearquestions #jeepreparation #jeenexus #arvindkaliasir #unacademy #straightlines
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TIMESTAMPS
0:00 Introduction and Nature of Chapter
3:09 Index and critical topics
5:10 Slope of a Straight line
18:23 Equations of a straight line
1:36:31 Angle between two lines
2:24:54 Some formulae (Distance of a point from a line)
2:32:54 Some formulae (Distance between 2 parallel lines)
2:41:15 Some formulae (Foot of perpendicular & Image of a point on line)
2:48:55 Some formulae (Area of parallelogram whose sides are given)
2:52:54 Family of lines
3:10:16 Locus problems
3:44:13 Equation of angle bisectors
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00:03 Complete the entire chapter of straight lines in one session
02:21 Understanding calculus problems and important concepts in straight lines
07:30 Understanding the concept of slope in straight lines
12:12 Understanding interception and slope calculation
22:16 Understanding the concepts of lines and interceptors in geometry
27:06 Understanding angles and equations of straight lines
36:13 Understanding reflection of lines and its implications
41:06 Finding the unique equation of a straight line passing through a given point with a given slope.
50:27 Understanding intercept form of a straight line
55:35 Understanding the properties of parallelograms.
1:05:51 Understanding alpha and its quadrants in the context of straight lines
1:10:41 Understanding parametric equations and parameters
1:20:13 Understanding parameter form of a straight line
1:26:54 The video discusses the intercept form and solving straight line problems.
1:38:35 Perpendicular line holds when slopes are non-zero
1:44:04 Understanding point of intersection and its significance
1:57:26 Understanding the concept of perpendicular lines
2:03:05 Understanding slopes and angles of straight lines
2:12:36 Understanding the different lines and their properties
2:17:27 Understanding parametric equations for lines and points on lines
2:28:40 Calculating distance and equation of straight lines
2:35:27 Explaining the intercept of a line between two lines
2:47:55 Understanding slope-intercept form and parallel lines.
2:53:56 Equation of the family of lines through a fixed point
3:03:40 Understanding the order of writing straight lines
3:09:00 Understanding the concept of straight lines and variable points
3:19:47 Understanding the process of eliminating variables from equations.
3:23:38 Identify fixed points and centroid of a triangle
3:32:05 Understanding straight lines and their equations
3:38:15 Understanding the concepts of straight lines and solving related questions.
3:46:46 Understanding of angle bisector and its implications
3:52:29 Discussions on angle bisector in geometry

Broskii-jqbq
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FunFact : Every chapter is IMPORTANT☠️

MartinG
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I think shera is a jee dropper who dropped for jee in 2000 and is still trying to get qualified in jee.

Shera:favourite student of arvind kalia sir
😂😂😂

cutegirl-tpnw
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TIMESTAMPS
0:00 Introduction and Nature of Chapter
3:09 Index and critical topics
5:10 Slope of a Straight line
18:23 Equations of a straight line
1:36:31 Angle between two lines
2:24:54 Some formulae (Distance of a point from a line)
2:32:54 Some formulae (Distance between 2 parallel lines)
2:41:15 Some formulae (Foot of perpendicular & Image of a point on line)
2:48:55 Some formulae (Area of parallelogram whose sides are given)
2:52:54 Family of lines
3:10:16 Locus problems
3:44:13 Equation of angle bisectors

ashwin.d
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🔥🔥🔥🔥🔥
🙏Dear Arvind Sir🙏,
🔹Could you kindly create a video demonstrating how to effectively address intermidiate-level questions using ✨Graphical Methods✨, particularly focusing on ⚪coordinate geometry and ⚪trigonometry?

This will really going to help me a lot!!

THANK YOU
🔥#POSITIVITY, BHAI MERA BHAI🔥

sharthakravi
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Sir at 3:25:50, you've solved it great, but, when I paused the video ( which is of course what you always say to students), I simply applied first centroid formula, then wrote, then I got x1;y1. wrt h and k. Then I simply put it in eq^n and got the answer myself.

varaddudhal
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Sir I am from class 12 I need the pyq session of class 11 chapter plzzzz

sagarmalviya
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Sir thank you so much you made all the concept so easy, love you ❤

blazeEdits
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Thanks a lot for the session bhaii
Obb session bhaii ❤
Guys jinko bhi st lines mein dikkat aa rhi .. u can do refer this session
Bhai ne tod tod ke bataya
And End to End solving jaroor karlena guys!!

Happy Learning folk!!

jakkavaishnavi
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In the question 2:45:31, Couldn't D) 8/5, 29/5 be also the answer. My approach to this problem is as follows:-)

By Intercept form -> X/3 + Y/1 = 1
We get equation of line to be X+3Y=3.

Now let (h, k) be the mirror image of the point (-1, -4) w.r.t to the the given line.
Since, (h, k) is mirror image, both (h, k) and (-1, -4) will be equidistant from the given line, so the one of the point on X+3Y=3 will be ( (h-1)/2, (k-4)/4).
Put this in equation
(h-1)/2 + 3(k-4)/2 = 3
From here, h+3k = 19. Now by putting values from option Both (1) 11/5, 28/5 and (4) 8/5, 29/5 are satisfying.

Crk-otum
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sir are these lectures sufficient for those whose lectures were missed in the coaching? 11th to meri bahut bekar jaa rahi hai 10th me 97percent aagyi thi itna low feel hua tha kyuki saare dosto ki usse jyada thi ab 11th me krne ko to jee ki taiyari ho rahi hai jisme meri kaafi backlog hogyi na test diye.abhi 11th ka half yearly ka result aaya to 75 percent aayi..competitive me mujhe itne awards mila karte the par iss saal dene ka mann hi nahi kar raha hai kyuki lag raha hai ki kuch padha hi nahi, ulta kaafi close friends se dosti tut gayi crush vagera ho gaya jiske baad to focus ekdum chala gaya hai..parents ne itni badi badi expectation aur laga rakhi hai..suicide karne ka dum mere anadar hai nahi mai bahut pareshan hu apni zindagi se ye baat kisi se kahi bhi nahi jaa sakti varna alag mazak banega..im so done with life karu to karu kya

thekunna
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Sir in question jee main 6th sept..2020... I think we have measured angle from wrong side .. we have to measure that angle from the line that is normal to x=1

Markspecgaming
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Sir are these concepts and variety of questions enough and all variety of questions are covered in your vedio or not?
Plz tell 🙏🙏

ujmsywu
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Concept ho gaya super se bhi upper, you are legend sir

ptesutm
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1:43:00 / 3:57:21
Angle between two lines

Srishti_IITaspirant
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Sir aap kitne acche se padha te hain . Thankyou

upmaravva-exqy
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Thanks a lot bhaii I have a test on this chapter tomorrow
Love you Bhai ❤️🙂

jrntrfanboii
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he is the best teacher for maths and the best part is that he doesnot do shayari like BW

yashcodes
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Sir at 57:18
We could use another property of parallelogram by taking the measures of opp sides as equal and find the coordinate for D
And then find the slope for AD and hence then the equation will be derived .
I think this would take less time . ❤❤

jasmineriddle
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1:01:36 Normal Form - Eqn of straight line
1:11:39 Parametric Form
1:32:05 General Form

G.BharatiRao