❌ Horrors of JEE Integration 😭 JEE Mains 2024 | JEE 2025 | JEE Advanced 2024 | CBSE 2024 #jee

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* Simplify the expression:
* We can use the identities tan(x) = sin(x) / cos(x) and cosec(x) = 1 / sin(x) to rewrite the expression:
sin(x) tan(x) + cos(x) cosec(x) = sin(x) * (sin(x) / cos(x)) + cos(x) * (1 / sin(x))
= sin^2(x) / cos(x) + cos(x) / sin(x)
* Integrate using the formulas:
* Now we can integrate each term separately using the formulas for sin(x) and cos(x):
∫ (sin^2(x) / cos(x) + cos(x) / sin(x)) dx = -∫ cos(x) dx + ∫ sin(x) dx
= sin(x) - cos(x) + C
Therefore, the integral of sin x tan x + cos x cosec x is sin(x) - cos(x) + C

Bohot Jada Mehnat Lagi hai type karne me 😅

latestmoviewala
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Ye 2 saal wale bhaiya me mujhe apna chehra kyun dikh raha hai😅😅😅😅😅

Pawanmishraaa
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when you realize, this is a halwa integration qn

priyangshughoshxb
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Put that question equal to 'I' now solve 'I'
😂😂😂😂😂😂

AyushYadav-stkr
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Sahi ans hai
ln| secx+tanx| + ln|sinx| –sinx + C
Aur last me x ke jagah theata rakh Dena 👍

rajshreepatwa
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I'm in Motion institute, Integration topic tough hai but GB Sir ne ye topic hame bahut hi aasani se sikha diya 👍👌

ratnajain-bsdz
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Others : padai ka video
Me: ye bhi badminton khelta wo bhi yonex ke mehenge wale racket se😂😂

ahaanpandita
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This integration: 😂😂
But
Integration of √tanx : ☠️☠️
Solve this

subhajitnath
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Calculus and vector algebra was my fav chapter ❤

sumitIID
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Uss sawaal me direct product nikalo aur sin square theta ko 1-cos square theta kardo
Aur dusre plus wale part me niche wale cos square theta se cos theta =t lelo phir go upar uska derivative hai phir game jaisa khelke kaam tamam kardo

bishwaranjanmohapatra
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Ans> Log(secx + tanx) - sinx + log(sinx) +c

prt-tanish
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Bruhh
Pehle stanx ko sinx/cosx likho aur for sin¢2x ko 1-cos^2x likhdo jisse eqn bnjaaegi integration of secx+cosx
Second part ke lie cot theta ka integration krdo
Basic formulaes
Ez maths

pranjalbhardwaj
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No matter where u study in the future, integration is always terrifying 😂

idc
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The answer to this question is ln(secx + tanx / sinx) - sinx + c

palav
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Bhi tumhari bat suna ki background music ki bat

Lamba ha madam lamba😂😂😅😅

AnikeshSingh-tqbr
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Change tan x into sinx/cosx and cosec x as 1/sinx then ;
It becomes sin^2x / cos x + cosx /sinx then:
Write sin^2x as 1-cos^2x then seprate and solve and ans will be
ln|secx+tanx| + ln|sinx| - sinx + c ❤

satvikyadav
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§(tanx.sinx+cosecx.cosx)dx
By using formula tanx=sinx/cosx
Cosex=1/sinx
So we can write it
§(sinx. sinx /cosx+cosx .1/sinx
We know that cosx/sinx=cotx
and sin^2x=1-cos^2x
So
§(1-cos^2x/cosx+cotx)dx
§secxdx-§cosxdx+§cotxdx

Rahuljudiyal
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Abe ooi meri personal life kyu share kar rahe ho yrr mujhse puche bina case kar dunga 😂😂😂😂😂😂😂😂😂😂😂

ujjawalptdr
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Bro iska integration nahi hoga bcoz (dx) nhi he

hacksmode
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My ans is ln|secx+tanx|-sinx+ln|sinx|+c using a simple trigonometric formula and standard integration formulas

urctolp