How to fix `ValueError: invalid literal for int() with base 10: 'variable_na... in Python

Hello, Dedicated Coders! 🖥️💡

We're excited to share with you our newest video, "How to solve `ValueError: invalid literal for int() with base 10: 'variable_name'` when converting input to integer. in Python". 🎥 This series is meticulously designed to arm you with knowledge 🧠 and skills 🛠️ to overcome frequent coding challenges.

Today, we will decipher 🔎 and resolve a common error faced by Python coders: the bit hard to solve `ValueError: invalid literal for int() with base 10: 'variable_name'` when converting input to integer.. Here is a snapshot of the code of the video:

Troubling Scenario: ❗️

x = int(input("Enter a number: "))

Unwanted Result: 🚫
`ValueError: invalid literal for int() with base 10: 'variable_name'` when converting input to integer.

Effective Resolution: ✔️

try:
x = int(input("Enter a number: "))
except ValueError:
print("Please enter a valid integer.")


Desired Output: 🏁
Please enter a number: hello
Please enter a valid integer.

In this detailed walkthrough, we will illuminate 💡 the underlying cause of this error, and offer a comprehensive explanation: The error occurs when non-integer input is provided. Code2 handles the error gracefully by catching the `ValueError` and prompts the user to enter a valid integer, thereby correcting the issue. 🎯

Ready to demystify the NameError: name is not defined in your code? Click to watch the video now 🎬. If it aids you in your coding journey, kindly express your appreciation by hitting the like button 👍, and don't hesitate to enrich our coding community by sharing your questions or insights in the comments section 💬.

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