Implicit Differentiation

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9 years later and still being insanely helpful, what a treasure.

krispy
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Aren't there videos for partial differentiation?

avichalthakur
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I was conceptually stuck differentiating y^2 with respect to x and this was the perfect explanation that I needed! Fabulous, thank you!

sdparsons
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Great way of comparing the two ways of solving for dy/dx. Thanks.

izzyh
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thx for the explanation for why we multiply dy/dx when ever we differentiate y.

imperialrecker
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This helped me so much. Thank you Eddie, you don’t know how grateful I am for your work!

noacavassi
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Love this video so much! I was craving to find the video that show me derivative using transposition of terms, it makes me know why and when I should use the implicit differentiation clearly.

humanature
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Sir can you please make video on partial differentiation from basics.... Because it is creating problem for me in fluid mechanics

TheRAVI
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Why do we have to use the chain rule when differentiating y²? Does the Power Rule not work? I'm thinking it might work, but we don't use it because that way we wouldn't have that dy/dx term, correct?

mvixjdo
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In Implicit functions (IF) the "Dependent variable (DV) is NOT JUST a function of the Independent vaiable (IV)". So if IV is X then DV might be Y or G or a mixture of X and Y but not JUST a function of the IV or X. Some use explicit = numerical quantities and implicit for non numerical quantities but when dealing with (IF) it is more comprehensively defined as "When the DV is not just a function of IV"
Differentiation of that DV which is not a function of IV requires the chain rule.

qualquan
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He made 2 errors. First the sq. root is +/- and not just + making the first method more tedious. Second one should show all the steps of the chain rule making the second method look easier and the preferable method since one CANNOT always make Y explicit. So when trying to find dY^2/dX by chain rule he should show all the steps. So initially we should write d Y^2/dY and not dY^2/dX. Then one can easily see that dY^2/dY = 2Y and dY^2 = 2Y*dY. Then dividing both sides with dX we get dY^2/dX = 2Y*dY/dX.

qualquan
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An incredible explanation; it helped me understand very easily. Thank you so so so much!!!

Lilatom-pscv
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Cheer~~~implied though not plainly expressed.😊

Jason-os
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You explain things so well! Thank you!!

ayandas
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This is the thing, you focused on what is the most confusing part of solving implicit differentiation problems and made me understand. thank you :)

provezano
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A circle can be expressed as 2 functions: y = sqrt(r^2-x^2) (top half) and
y = - sqrt(r^2-x^2)(bottom half). when I do the derivitave of the top half I get
-x/y, just like with implicit differentiation. But when I do the bottom half, I get positive x/y. What am I doing wrong?

dawoool
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I like to teach chain rule outside first, then inside(s). In this order, the implicit is even easier - because you keep differentiating until you hit the bare 'y' term - and write dy/dx. 

Downside of reversing the order is you need to clean up the expression in most cases, but I think that's a benefit.

enzuber
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Wtf i was i tuned this with headset on almost busted my eardrum

mihlalidikwana
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Thank you very much now i understand differentiation watching ur series of videos about it instead of just memorizing the rules of differentiation and applying it !

MaverickCF
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you explain things so well, thank you!

kyaruh