dy/dx for r = 1/theta at pi

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slope of the tangent line to a polar curve, r = 1/theta,
dy/dx for r = 1/theta when theta = pi

S. Chow
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My second view of your videos this week. Thank you!

shawnweaver
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Hey, there's any way to transform that polar curve in rectagular coordinates?

vincenzomangino
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If i get -.2.632742843
where did i go wrong?

rat_king-