Lecture 22 - Examples and Second isomorphism theorem

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One important point: We do not need to prove that H intersection N is a normal subgroup of the group homomorphism because we we finally get it as the kernel of the homomorphism map.

atifzaheer
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Such a great detailed informative video. I can't be more grateful. Best wishes and regards

mofidw
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@06:20 I think the steps of derivation can be as below (noting that S' = e^(i theta) for theta in [0, 2pi])
C*/S'
= {rS': r \in R+}
= {|z| S': z \in C*}
= {|z| e^(i arg(z)) S': z \in C*}
= {z S': z \in C*}

RahulMadhavan
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Sir, you said about a particular case that G can be thought of as a subgroup of G' when G is homomorphic to G' and Ker (phi) is e only. But sir, how is it possible that if G and G' are defined with different operations..?

subhashjohnson
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Second Isomorphisam looks like corollary rather than Thereom

revanthkalavala
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I don't understand that why are there so less views?

artsandculture
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