Do you know your limits?

[tobybartels]

Probably 1. 0⁰ is usually 1. You have to set up the exceptions just so, and this doesn't look like that.

[vladimirrodriguez]

Following the succession of results the intuition indicates 1 for the last limit, however, the result is 0 for the successive x-th powers of the function x^x

[raphael]

The answer is 1 because 0^0 is usually defined as 1, at least where I'm from

[rahul_op]

I did it by taking log on both side and use previous limits as a result during solving other problems

[darcash]

plugged in some close to 0 arguments. it's 1

[naxnusternann]

Why is the third one 0? Wouldn’t be the same as the second one?

[mint]

i know nothing about what limits are but here's my attempt
the one with x^x^x=0
so x^x^x^x=x^0=1

[stayinthedark]

The answers are sort of pattern in binary order. The last one would probably 1 😅

[abolfazlabasnatj]

Isnt 0 to the power of 0 meaningless like 0÷0?

[aisagregori]

@bprpfast would you mind answering the question, no idea

[rythmx]

no, take a closer look, x^x^x^x generally means (x)^x^x^x
here if see the limit of x^x on the upper part, it goes to 1 so now you have x^x that is also 1, so 1^1 = 1
but with a different approach, (x)^x^x^x,
the limit of x^x^x, it goes to 0, technically 0 plus, so now you have 0^0 thats Indeterminate

[bddc]

Could you explain the logic behind it?

[ajaychauhan]

X^x^x = 0, last one will be one be because (x^x^x)^x = 0^0 = 1

[chrisng]

I think it's 1, it'll be 0 for odd height towers and 1 for even, cause lim(x^0) =1 and lim(x^1) =0

[thatomofolo]

King Jesus Christ Yeshua loves You 🤗♥️😊💫

[TheBrilliantShadow]

The answer is 1 because...





... I said so!
(And because it's right, we return to x^0=1)