Complex conjugates | Imaginary and complex numbers | Precalculus | Khan Academy

Complex Conjugates

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[RoshFragger]

I couldn't understand this concept for days... Now I can solve these questions with ease, thank you soo much Sal! : ))

[YashVerma_twistedsoul]

There is one mistake in this video which he even corrected. If you guys just wanna criticize then go get a tutor for yourself +Oliver Walter. Great job khan academy, you really cleared all my doubts

[omargamal]

The sad thing is I've learnt more from you, than 4 years of all my engineering professor at one of the best Universities in Canada

[pro-films]

Thanks a lot mann this world need more humans like you 🙌🏻♥️

[DandoBorusu]

Hey team, your answer should be =(2/3)+(13/9

4^2+(5i)^2=16-25=9

[MoeTechhh]

this was very useful thank you but when u put 4+5 on 4+4 u got me thinking so hard until u put it back 4+5 on 4+5 😂

[diausabastien]

learning complex numbers so that i can complete my java program

[cangishigo]

I am sorry, at 6:44, why do we get 1 from i squared?

[laducki]

Thank you. The material my university provided didn't have enough examples so it was hard to grasp. Now I understand this better.

[AlphaFoxDelta]

How do some people not find this absolutely awesome?

[kronologie]

You sure that's a 5i bro? lol 5:00

[sidnierecmanginsay]

Thanks man! And thank God for giving you such knowledge and you share it to us!

[액티비아]

한국어 자막 누구에요? 기대도 안하고 들어왔는데 반갑자너...감사합니다. 덕분에 배속으로 듣네요 :)

[cloudproblemssolved]

I wish I could write the bar over z in Mathway

[davidmurphy]

But why did this work?! I tried it and it does but right now I'm putting it down to witchcraft! ;)

[MichIsCool]

I lol'd when he saw the 5i mistake

[cloudproblemssolved]

They actually want the real number scaling the i, not the whole term, I learned something new 😂

[BlaiseIgirubuntu]

@wetim99
By definition, i is the square root of -1, therefore i²=-1

[husseinallaithi]

Oh You Have No Idea How Much I Struggled Until Now I Hope

[Niko]

By definition, i^2 = -1. It is actually not defined as i = sqrt(-1). I hope it helps :)