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Derivation of s = ut + ½ at² || 2nd equation of motion || Algebraic method || Motion, class 9
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About this video:
Hello geniuses, in this video you will learn to derive the second equation of motion i.e s = ut + ½ at². This video is in a very simple language so that students can understand the derivation easily.
In this video you will get the complete step by step calculation with it's explanations.
Also, this video is extremely beneficial for the students of both class 9th & 10th. Thus, I hope that you will enjoy watching this video.
Derivation:
Suppose, a body has an initial velocity ‘u’ and a uniform acceleration ‘a’ for time ‘t’ so that its final velocity becomes ‘v’. Let the distance travelled by this body in this time be ‘s’.
Now, Distance travelled = Average velocity × time
i.e., s = [(u + v)/2] × t [ average velocity = (u + v)/2 ]
i.e., s = [(u + u +at)/2] × t [using 1st equation]
i.e., s = (2ut + at²)/2
i.e., s = ut + ½ at²
Imp link:
#s=ut+½at²
#Motion9
Hello geniuses, in this video you will learn to derive the second equation of motion i.e s = ut + ½ at². This video is in a very simple language so that students can understand the derivation easily.
In this video you will get the complete step by step calculation with it's explanations.
Also, this video is extremely beneficial for the students of both class 9th & 10th. Thus, I hope that you will enjoy watching this video.
Derivation:
Suppose, a body has an initial velocity ‘u’ and a uniform acceleration ‘a’ for time ‘t’ so that its final velocity becomes ‘v’. Let the distance travelled by this body in this time be ‘s’.
Now, Distance travelled = Average velocity × time
i.e., s = [(u + v)/2] × t [ average velocity = (u + v)/2 ]
i.e., s = [(u + u +at)/2] × t [using 1st equation]
i.e., s = (2ut + at²)/2
i.e., s = ut + ½ at²
Imp link:
#s=ut+½at²
#Motion9
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