LeetCode 169 Majority Element Solution in Python | Easy Interview Problem Tutorial

Solve LeetCode 169 "Majority Element" in Python with this beginner-friendly tutorial! This easy problem asks you to find the majority element in an array (appears more than n/2 times). We’ll use `max()` with a `lambda` function to find the most frequent element in `[3, 2, 3]`, and explain the one-liner solution. Perfect for coding interview prep, Python learners, or anyone tackling LeetCode array challenges with a focus on majority elements!

🔍 **What You'll Learn:**
- Understanding the Majority Element problem
- Using `max()` and `lambda` to find the most frequent element
- Leveraging sets for unique elements
- Testing with LeetCode test cases

💻 **Code Used in This Video:**
class Solution:
def majorityElement(self, nums):
# Type: List[int]
# rtype: int
# Find element with highest count using max and lambda
return mode

# Test cases
nums1 = [3, 2, 3]
print(Solution().majorityElement(nums1)) # Output: 3

nums2 = [2, 2, 1, 1, 1, 2, 2]
print(Solution().majorityElement(nums2)) # Output: 2

🌟 **Why Solve LeetCode 169?**

📚 **Who’s This For?**
- Python beginners tackling LeetCode
- Coders prepping for tech interviews

# LeetCode 169 Majority Element
class Solution:
def majorityElement(self, nums):
# Type: List[int]
# rtype: int
# Use max with lambda to find the element with highest count
return mode
# set(nums) gets unique elements
# max() returns the element with the highest count

# Test cases
nums1 = [3, 2, 3]
print(Solution().majorityElement(nums1)) # Output: 3 (appears 2/3 times)

nums2 = [2, 2, 1, 1, 1, 2, 2]
print(Solution().majorityElement(nums2)) # Output: 2 (appears 4/7 times)
- LeetCode enthusiasts solving easy problems

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