Calculus 2: Hyperbolic Functions (38 of 57) Finding arc(cschx)=?

In this video I will find y=(csch)^-1(x)=? or y=arccsch(x)=?

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[SandileNcube-vikg]

simple and straight foward explanation, thank you very much greatly appreciated

[albertomontecarlo]

I think there is a mistake in the definition, , , if you write the form as you did csch-1x = ln (1/x(1+……) you don’t allow y to be negative and there is no restriction on y, , , I think it’s correct to put csch-1x= ln(1/x+ Square root of 1+x2/ absolute value of x, , , the absolute value allows y to be positive and negative as it should be, ..

[sin_x]

I have a question!
arc(cschx) is ln [(1 + sqrt(1+x^2))/x] at x =/= 0.
But when x is negetive, ln can not be defined!

[황주현]

Best explanation!! I understand at once