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If in two triangles ABC and PQR, AB/QR=BC/PR=CA/PQ, then(A) PQR∼CAB (B) PQR∼ABC -(C) CBA∼PQR (D) ...
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If in two triangles ABC and PQR, AB/QR=BC/PR=CA/PQ, then(A) PQR∼CAB
(B) PQR∼ABC
-(C) CBA∼PQR
(D) BCA∼PQR
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(B) PQR∼ABC
-(C) CBA∼PQR
(D) BCA∼PQR
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