Mechanics of Materials: Lesson 5 - Bearing Stress Explained, Example Problem

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Your videos have helped me through Statics, Strength of Materials, Structural Analysis, and Indeterminate Structures.

I am an engineer now, but still in school. I can't thank you enough for all the times you've helped me over the years!

masterblake
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I love the way you explain the whole thing. Simple and easy ! Thanks

mohamedkhalid
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Keep it up professor 💪💪 you’re doing wonders for us mechanical engineering students

rma
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Can you make a video explaining why projection is used as opposed to cylindrical contact area.

sshep
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ohh may daysss, finally the best professor is back.

navidahmed
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In this course right now, perfect timing

gabewinter
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This is the best explanation I've heard!! Absolute life saver. Sending love from new zealand

PeterParker-szvm
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Miss you dr Hanson! Hope all is going well at tech!

CRatcliffe
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Wonderful solids lessons!! really taking the time to explain the problems along with a good sense of humor :))

manuboker
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I have a question. At 10:20 he assumed to measure Fab as Fab(cos50) but wouldn’t it be cos40 bc you measure the angle from the horizontal? Someone please clarify thank you!!

mr.flubberblubbersprinkles
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Need to keep up the videos. Once per week would be epic if you can sir. You were thinking of moving onto other topics once upon a time 😊

owencarlisle
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Hi, professor. Why the area in the bearing stress isn't 3.14(4.5)(15)? because it's half the perimeter times the thickness, that the surface that the bold hold the force with it.

A.Hisham
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is it ok to use the same force for both shearing and bearing?cause bearing is normal strress and shearing is not

DaryaDelaram-xx
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@9:24 why did you make F_ABsin50 on the horizontal and F_ABcos50 on the vertical. Initially I paused the video and went ahead and did my own calculation but with the moment at point B. I Got stumped not realizing you had your sin and cos mixed up. If I recalculated my moment to have it at point C, I realize I wouldve got the same answers as before. So im just lost on why x is sin and y is cos.

javierumana
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So how do we find the normal stress here? What should be the area for Normal Stress?

famueduyou
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hello, here in this video, we didn't transform from mm to m because we are dividing in the end and it will simplify true??

charbelbassil
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Can someone explain how he arrived at the angle 20 at F(AB) to get the overall angle of 50 deg?😪😮‍💨☹🥴😖😫

joeking
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For A I got 702.47Pa, since I converted the mm diameter to m when calculating area. How is my answer wildly different from yours?

AlbertVathapally
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I'm still struggling to understand why you have to find the resultant force at pin A and then divide by the area. I thought the shear force was only on the "y" direction

alanlopez
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Come on, man. I just graduated. Where were you 7 months ago??

walter