Prove that if a/b = c/d = e/f then (a^3b + 2c^2e - 3ae^2f)/(b^4 + 2d^2f - 3bf^3) = (ace)/(bdf)

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Prove that if a/b = c/d = e/f then (a^3b + 2c^2e - 3ae^2f)/(b^4 + 2d^2f - 3bf^3) = (ace)/(bdf)

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I'm no linguist, but the Douey-Rheims Bible, the one recommended to Traditional Catholics, written by St Jerome, i.e.~1600's, "show" is spelled "shew" lots of other biblical words are spelled differently as well, i.e. Noe is Noah. Thanks for working these problems, they are more fun than "must see TV". XoXo

susann.

The word "shew" is an archaic spelling of the word "show". It fell out of favor by the 1920's. Higher Algebra by Hall and Knight was originally published in 1887. The archaic spelling popped out at me in something I read recently, but I don't recall the exact text at the moment, unfortunately.

mikecaetano

That is a very good algebra book. I haven't tried it yet, but soon I will start.
🙂

Nicely done.

dharmavarta

Vary satisfying to see 👀 It all collapse so neatly.

urekah

This is a "really good shew, " as Ed Sullivan would say ... hehehe. Great channel and fun problem. Cheers

algorithminc.

if a=0;c=0;e=0; then b, d, f can be any value.
but let b=1; d=2; then f cannot = 0; and f=approx -0.17; -1.32; 1.50
then i saw he did it on a theoretical fashion. i am applied math. oh well.
this has multiple real answers.
his proof is circular; because there are real answers.

fred

You keep smelling your books. That musky smell is mold like in bowling alleys because of bowling shoes. The author told you this. He said, "shoe that..."

Edit: Get a whiff of this tasty proof.

bradleybeauclair

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