If a ≡ b (mod m ) , then prove that a^n ≡ b^n (mod m) || Property of Congruence || Number theory.

preview_player
Показать описание
Thanks for watching ................
---------------------------------------------------------------------------------------------------------------------
Рекомендации по теме
Комментарии
Автор

what did he say from 0:59 to 1:10 I want to know his reasoning behind why his base case is true

giselle-cwvd
Автор

today is the first day i iwished i learned indian instead of spanish

yon