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If asinθ+bcosθ=c, then prove that acosθ−bsinθ=√a2+b2−c2
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If asinθ+bcosθ = c, then prove that acosθ−bsinθ = ±√a²+b²−c² #class10thmaths
If acosθ-bsinθ=c prove that asinθ+bcosθ= ±√a2+b2-c2. RS Aggarwal Exercise 13B class 10, Example 13....
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