How to Solve a Buoyant Force Problem - Simple Example

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We use Archimedes' Principle to determine the number of penguins an ice float can dryly support.
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you never know how much it help student in 2021....

fbi
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I've watched too many density videos that I could not understand, you my friend, have explained this crystal clear

alexandarbezanovski
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Thank you very much! Nothing else explained buoyancy as simple and clear as yours. Indeed a great teacher!

jekunP
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Very brilliant, helpful explanation, deserves more recommends. And I liked the inclusion of the penguins; they kept my spirits cheerful and buoyant.

helenday
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Great Video! Made Archimedes' Principle very clear, I can tell you are a great teacher!

mollymiller
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Excellent job! I needed a refresher and this was the perfect introductory problem. Not too easy, but not too challenging!

lionbearpolarbear
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Excellent => from a broad, "outer" zoom concerning all possible principles that MAY be used to an "inner" zoom that is most usually presented in text books.... Thank you for sharing.

saintgregoiredarmeniemonas
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I saw a picture of a slice of pumpkin pie floating on top of an open container of cool whip.
Of course the density of the cool whip is very low compared to the pumpkin pie. Perhaps the pie was slowly sinking when the pic was taken and so viscosity would be a factor.
I also don’t know the temperature of the cool whip (pronounced “cool whhhip”) which I suppose would be a factor related to density.
One thing is clear, this buoyancy scenario warrants lengthy experimentation.

greggjohnson
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Wow, this way of approaching a problem is awesome! For me, after establishing an equation, I would solve it straight away. Now I come to realise that it is convenient to further 'disassemble' the equation, if that is correct

nazmiimtiyaz
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I love the walken impression at the end.

Prince_Sharming
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Thank you so so so much. I've been stuck with a similar problem for 3 hours.
Happy Easter dude!

addadd
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You should make more videos! You are amazing. I subscribed and looking forward to more content!

funnyever
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If that ice is 1m thick, that must be a huge penguin.

housevidios
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why is normal acting in downward direction in the above problem???

shilpiagarwal
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This video needs more views, it is so helpful!!!

Jadamog
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you're definitely ;earned and brilliant!
thanks a lot bro!
please upload more!

arpitsharma
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a barge has vertical sides and a flat bottom of 320ft^2 area. when partially filled, the barge is immersed in fresh water to a depth of 2.00 ft. upon removal of the load the barge rises 16.0 in. (a) what is the approximate weight of the barge? (b) what vertical displacement will result if a 10 ton truck is loaded on the barge? PLS ANSWER

ogmiracle
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Hmm, out of curiosity... couldnt I just;
1) Work out the buoyant force (Up), and the weight force (down) of the ice
2) Then minus the weight force from the buoyant force
3) The remainder buoyant force value, would be indicative of how much additional weight force (of the penguins) could be added, yes?

jewels
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Hey Jesse, so I tried this principle out today in real life: I had a 40 kg plywood board (the ice), a 25 kg sandbag full of stones (the penguin) and into fresh water (Density of 997 kg/m3). The calculations came in at 0.713 sandbags required (70% of 25kg) to sink the plywood board (2.438 x 1.2192 x 0.01905 m3) but yet when placed in water it floated. So I upped the sandbag mass to 30 kg (15 kg in each one) and attached them to the board and pushed them off when in the water. The board still never sank! Can you help at all please?

owenjones
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thanks! Learned some physics, plus, how to draw a penguin. Progress!

davidwright