A Wonderful Math Problem. Ln(1+i)=? Complex Number.

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i did it in seconds by finding the tangent. dividing the Im{1+i} by the Re{1+i} since Re{} gives cos and Im gives sin. using this I get i/1 which is i. (basically this means that this complex number has a slope of 1). I knew that arctan of such is pi/4 giving theta to be pi/4 + n2pi | n is an integer. the magnitude of this complex number is sqrt(2) giving us r.

davidhjedwy
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cant ln(sqrt2) be simplified as ln(2)/2

axbs