Inverse Trigonometric Derivatives f(x) = arcsec(x/2)

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Inverse Trigonometric Derivatives f(x) = arcsec(x/2)
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THANK YOU! I've been searching for a clear explanation for a problem like this for hours. I don't understand why other "instructors" can't just simply explain the process like this. Anyway, thanks again, cleared up my thoughts and a huge headache.

MiddleCross
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Yeah I’m just gonna leave it in simplified hopefully I don’t lose a pint on the test

youngman