Permutation and Combination One Shot | Class 11 Maths NCERT Chapter 7 by Ushank Sir Science and Fun

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Permutation and Combination One Shot | Class 11 Maths NCERT Chapter 7 by Ushank Sir Science and Fun

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[scienceandfuneducation]

Hello bacho event like karo jaldi jaldi !

[anjaliraj]

0:00 Indroduction
2:50 Fundamental principles of Counting
27:02 Factorials
39:09 Permutation
1:22:47 Combination

[kshitizgambhir]

1:47:33 The question asks that how many words are listed in dictionary when we open the dictionary before E letter. Means we have to tell all the words coming before letter E no matter what is the meaning without repetition other than given in the word " EXAMINATION" . @ushakghai sir

[vkx_editx]

10:31 3x2x5 = 30 different ways
11:09 115x45x16 = 80800 ways
22:47 10 digits i.e. 0, 1, 2, 3, 4, 5, 6, 7, 8, 9

[raghavbairagi-mzgt]

1:47:33 H.W. Q. = We have to put the first letter A and find the permutations of other 11 letters, so that we can find all the words that list before the first letter E. ❤

[ganeshshinde]

1:47:33 If the different permutations of all the letter of the word EXAMINATION are listed as in a dictionary, how many words are there in this list before the first word starting with E?
Answers:
Alphabetically only A before E in the letters of word EXAMINATION So only words starting with A letter befor the the first letter starting with E letter
.•. number of ways =
(AA ) EXMINTION
thereis 10 leters but A is always 1st
.•.9! In this 9 letters I & N is repeating 2 times so 9!/2!•2!

[EdEd-pfye]

1:47:33Answer
The letters of the given word are
A, A, E, I, I, M, N, N, O, T, X, i.e, Word starting with A are formed with the letters 2 I's, 2 N's, A, E, X, M, T, O (total 10 letters).

Hence, number of words formed by these letters

=10! /
2!2!

=10×9×8×7×6×5×4×3×2×1/
2×1×2×1

= 10×9×8×7×6×5×3×2×1/
4

= 907200 ways

[yush]

54:10 Total ways 120 and even numbers 48

[RakeshKumarYadav-vgux]

I think some of you must have thought about it once in your life that I used to think, How can there be so many phone number with just 10 numbers? And now I know that there can be 10^10 ways to write a phone no. which is equals to 10 billion where Earth's population is 8 billion, which means even if we give each person on Earth a different phone number we still have 2 billion different phone number we can give 🤯😵😂

[Sam..]

0:00 Indroduction
2:50 Fundamental principles of Counting
27:02 Factorials
39:09 Permutation
1:22:47 Combination

[subhamkumar]

The letters are arranged in a dictionary in alphabetical order. Therefore, in this question, we have to find the number of words starting with A, B, C, D to get the number of words before the first word starting with E appears.
Therefore,
We first try to find the total number of words starting with A. For this, we fix A at the beginning and find the different permutation of the other letters after that.
As the total number of letters in EXAMINATION is 11, the words starting with A should be of the form A _ _ _ _ _ _ _ _ _ _
Now, after taking out A, the remaining letters are E, X, M, I, N, A, T, I, O, N.
We know that the number of distinct permutations of n objects (having k distinct objects repeated one or more times) in which object 1 is repeated p1
times, object 2 is repeated p2
times etc. is given by n!p1!p2!p3!...pk!
However, we note that of these remaining letters, there are two I’s and two N’s which are identical. Thus, using equation (1.1) the number of distinct permutation of the remaining letters are 10!2!2!=907200
Thus, the number of words from the letters of EXAMINATION are 907200.
As B, C and D are not present in the letters of the word EXAMINATION, the total number of words in the list before the first word starting with E is equal to the number of words starting with A, which is 907200.
Note: In this question it is necessary to divide 10! by 2! and 2! in equation (1.2) because the words in which the two I’s or two N’s would be interchanged would correspond to the same word in the dictionary.

[deepakx]

54:00 total numbers will be 120 out of which 48 are even ❤😊 1:17 cases when I not come together is 33810 1:47:00 sir this question means that we have to arrange all the words in dictionary pattern first letter will start from A and then so on 1:15:04 ans1 is 420 ways ans 2 is 778320

[gunulivevlogs]

1:47:30 ans of words with using word ‘EXAMINATION’ that are in dictionary before the first word starting with E are 9, 07, 200
A_ _ _ _ _ _ _ _ __
Using 10!/2!2!

[kajalsen]

Timestamp:- 1:12:38
All vowels occur together= 240

[ShreyaKumari-bj]

1:16:46
Total no of ways- 34650
Ans - 33180

[ashutoshupadhyay]

1:25:45

Sir moka to do icecream choose krne ka😂😂tab na hate to sir i really like the way he teaches ❤❤❤😊😊😊

[Scooby-Doo-lu]

Legends are watching this just 2 hours before half yearly exams

[ArjunSharma-dqex]

54:12 Normal Answer =120, even answer=48

[Lopa]

1:12:36 MONDAY - all vowels occurred together - 240 ways

[musicmusic]

1:47:33 sir iska matlab hai ki, humara jo word examination hai, uske sare permutations are diff, toh Hume number of arrangements batani hai, for jitne bhi words "E" se phele ayenge, because dictionary main words A-Z arrange hote hai