Integral of 1/(sin^2(x)cos^2(x))

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How to integrate 1/(sin^2(x)cos^2(x)).
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good video sir
i solved this question by this method:
integration 1/sin^x.cos^x
integration sec^2x.cosec^2x
integration (1+tan^2x)cosec^2x
integration
integration cosec^2x+sec^2x
= -cotx+tanx+c
=tanx-cotx+c
=sinx/cosx-cosx/sinx+c
=sin^x-cos^x/sinxcosx+c
=-2(cos^x-sin^x)/2sinxcosx+c
=-2cos2x/sin2x+c
=-2cot2x+c

factsandcoding
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Why go into such hardships when you can just and then it becomes straightforward? I am not saying you are wrong, but this is something it would take efforts to check.

redcat
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Thankyou sir. I was searching this method.

jailogic
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Hey White board math for which classes your preparing videos

nikhilbhiwandkar
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In nootan physics´ ch 0; ans is given as tan x- cot x. WHY SO?

mainaksen
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I know its off topic bt you voice.. it's so.. I love it!




Edit: can't say the word as it's a maths platform 😁

detectivelskawaiiimouto
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Gracias, aunque hablo español he entendido tu video, hahaha...

Aunque en mi libro el resultado queda distinto :'v supongo que el libro no trabajó con la identidad trigonométrica que tú usaste al inicio. Sorry for the spanish.

yisus
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12th bharti bhawan part2 book ka solution chahiye kar dijiye pls

leorajsingh
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It is wrong.... The correct answer is tanx - cotx + C .... Exercise 7.2 q.39 ncert class maths 12 part II

ganeshsubramanian
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Hhhh stupide question what is cot ? And cosec ? I’m very weak in mathematices 😢😢😖😖😓

parksana
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Brother simple to [ sin^2=1-cos2x]and [cos^2=1+cos2x]

vijaymahawar
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yep know it's sur am not a math person i will fall my exam

mohammedmarniche
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1/(sin²x.cos²x)=sec²x.cosec²x, obviously
Now we know that sec²x.cosec²x=sec²x+cosec²c
So it would become tanx-cotx+c

babahijacker