Calculus 2: How Do You Integrate? (8 of 300) A Product of 2 Functions

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In this video I will show the method of using the integration by parts method to find the integral of a product.

Next video in the series can be seen at:
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8 of 300...
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hamadalmehrizi
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Thank you for sharing this wonderful video. I'm a big fan of all your videos. At 0.42, I believe that dx is extra and not needed, it should only be u dv (or u v').

baher
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I am confused about the step where you rewrote the part by integration formula. Specifically, how du changed to the derivative of u.

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