Class 10 Maths | Chapter 3 | Exercise 3.5 Q4 iv | Pair Of Linear Equations in Two Variables | NCERT

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In this session we will be continuing with the chapter "Pair Of Linear Equations in Two Variables".
We will cover Exercise 3.5 Q4 iv of chapter 3.

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karan
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The explanation was very clear, thank u.

shreyakumari
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I loved ur way of teaching and speaking too

chinmayabehera
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ganeshpandit
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I can't able to understand the first case, but after your explanation, it's really outstanding ma'am

faadilahmanala
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babrabeigh
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mrinalsabharwal
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mam in speed formula ..distance upon time we had not taken the SI unit of time as second and do calculations with time in form of hour so why mam we did not do it in SI unit ???

jaitigangwal
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Thank you mam I can't understand this question but when I see your video it get stood in my mind

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devanshpanwar
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Explanation was understood able
Nice

rohittiwary
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Mam ac kaa time 5hour too samjh mai aaa gya but bc kaa time 5 hours kaise hoga kyuki dono hii total 5hours Kai badd meet hoo rahe hai too fir yai kise hua

ravindarakumar
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very nice explanation thanks a lot madam

arpandey
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Thank youu so much mam💕
It really helped me alott!!🥰

mauligakhar
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Mam Etna bada likhane ki kya jarurat hai


Speed =distance/time
Case 1 let speed x
Distance 100+y
Time 5 hour
x= 100+y/5
x-y= 100/5
x-y= 20 (1)

Case 2
Let speed x
Distance 100-y
Time 1
x = 100-y/1
x-y = 100

By ELIMINATION method
x-y =20
x-y= 100
Get 2y=80
y= 40
Put the value of y in equation (1)
x-40=20
x =20+40
x= 60


Therefore speed of both car are 60km/h and 40 km/h

blqsdgd
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justaakss
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RakeshKumar-zsoi
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Mam ye wala question app to pura bohot easily samjha halwa thank u so much mam😊

legendtone
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Mam thoda language lilho maths mai language ka upyog hota ha plz mam

mamtabhadri
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Thank you maam ap bohat acha pharti ho

Qazi