Measure Theory 7 | Monotone Convergence Theorem (and more) [dark version]

preview_player
Показать описание


Please consider to support me if this video was helpful such that I can continue to produce them :)

🙏 Thanks to all supporters! They are mentioned in the credits of the video :)

This is part 7 of 22 videos.

#MeasureTheory
#Analysis
#Integral
#Calculus
#Measures
#Mathematics
#Probability

I hope that this helps students, pupils and others. Have fun!

(This explanation fits to lectures for students in their first and second year of study: Mathematics for physicists, Mathematics for the natural science, Mathematics for engineers and so on)

Рекомендации по теме
Комментарии
Автор

This is very beautiful the way you explaind. Here is a request, please mention at least one example on each theorem or lemma. It'll be helpful in applications.
Thank you!

Mzemze-ox
Автор

I'm not following an aspect of the part b proof.
As far as I can tell, what was proven is:
Suppose A is a subset of X. Then if f(A) = g(A), g(X-A) = 0, and f(X-A) >= 0, then the lebesgue integral of f over X is greater than or equal to the lebesgue integral of g over X.
As we have not actually addressed something like, for instance, g(x) = f(x)/2. A function where everywhere f(x) > 0, g(x) > 0

alphachief