PRMO 2021 - INEQUALTIES | AM - GM INEQUALITY | PRMO Exam | PRMO Preparation | Abhay Mahajan | VOS

preview_player
Показать описание

➡Register For OMM Level 7 for Grade 8 -12 Students:

➡Register For OMM Level 5 for Grade 7 & 8 Students:

➡Register For OMM Level 6 for Grade 9 & 10 Students:

➡Register For 11th Maths & IOQM for Grade 9 -11 Students :

➡Register For ISI + JEE Maths 2025 for Grade 12 & 12th Pass Students:

➡Register For Full Math Mastery 2026 for Grade 9 -11 Students :

➡Register For Calculus 2024 for Grade 9 -11 Students :



#IOQM #rmo2023 #ioqm2024 #RMO #inmo #mathslover #matheolympiad #olympiads #VOS #VedantuOlympiadSchool #olympiads #olympiadpreparation #isientranceexam #jeemains #isikolkata #jeemathstricks #jeemathspreparation
Рекомендации по теме
Комментарии
Автор

Lecture starts at 16:17
SAVE your TIME😊

raghavsharma
Автор

Sir you and Prashant Jain Sir are definition of Olympiads

apjabdulkalamfanatm
Автор

For Q9. I cracked this question but my approach may not seem good:-
∑ (kx^k)/(1+ x^2k) = n(n+1)/2
2( (x)/(1+x^2) + (2x^2)/(1+x^4) + (3x^3)/(1+x^6) + ... + (nx^n)/(1+ n^2n)) = n(n+1)/2

Put x=1
2( 1/2 + 2/2 + 3/2 + ... + n/2) = n(n+1)/2
If you carefully see then L.H.S= R.H.S as in LHS we get n(n+1)/4 * 2= n(n+1)/2. So, x=1 satisfies.

If you put x=2 or any other natural number, it will not form a series of sum of consecutive terms within the bracket which will never be equal to R.H.S.
E.g. x=2
2( 2/5 + 8/17 + 24/65 + ... + 2^n(n)/4n+1) and general term as you see will be 2^n(n)/4n+1 which is not equal to n(n+1)/4 which should be desired within bracket in order to equate it with RHS, thus only x=1 satisfies.

themythagoras
Автор

in the question at 41:53 we can also use cauchy schwarz inequality also

JISHART
Автор

Please anyone help me
At 51:11, there is 4-C3(2.2.2), here if we add 4+3=-7*8=-56 which is wrong and then -4+4=-1*8=-8 which is again wrong, so how we got -32? What is tye meaning of 4-C3?

ramkumarmishra
Автор

sir q8 mei pehle am hm phir gm hm use karke nikal sakte hai?

shashwatsharma
Автор

1:02:19
Sir do u take doubt sessions?

Khushighmet
Автор

Q. Find maximum value of 2-a-(1/2a), a is positive
My answer:
(2-a-1/2a)/3 >= √1
(AM) (GM)

2-a-1/2a >= 3
Therefore maximum value is infinity.
but the real answer that is given is 2-sqrt(2). Please reply

mihirramaswamy
Автор

Sir, please upload the solution of geometry of Pre College mathematics

brajeshkurmarrai
Автор

Q 8 mein main rmo mein last tak bana ke wo nhi soch paya 😂😂😂

castor
Автор

ToT (>< | ><)
____

negipro
visit shbcf.ru