Calculus - Introduction to Continuous and Discontinuous Functions | Don't Memorise

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[anamikajha]

5:28 no, it is not a continuous function because the input negative 1 is not included and the graph directly jumps from just before negative 1 to just after it. Maybe marking negative 1 would give us an imaginary number or an undefined fraction.

[aaachannel]

I thought that this voice was computer generated but after seeing the mam I really shocked
❤️ This is the best channel ever

[amanvishwakarma]

thanks a lot, yesterday i started this chapter and i was unable to understand it but now you made it very easy to me. once again thankyou so much.

[pwsk]

Back to calculus!
You don't know how much I love it. Thank you. Also narrator mam is back, the perfect match. Go on,
"KEEP CALM AND LEARN CALCULUS "😅

[theyaghu]

final question answer is discontinuous at x=-1

[ismailhamza]

I always find peace with explanations from this channel. Hat off

[vamikasagwal]

Really
I really like the way of ur teaching
Hats off 2 u and ur work dear😊😊

[esm-world]

What a coincidence
Today I started a topic in class 12 chapter 6 ncert maths
Continuity and differentiation and when I come to utube to search that Topic And suddenly I got a notification from don't memorise
Continuity and discontinuity
Shocked that don't memorise read my mind 😂😂😂

[cuteworld]

Thank you don't memorise, for making this concept a simpler one. 🥰🥰

[priyadarshinisingh]

I was searching for this vedio tomorrow on your channel 😄😄😄

[princesehgal]

After long time i hear Zarina mam voice
Nice voice mam

[vedhkamble]

Excellent video for students please make more videos on this topic.

[alphaish]

It would be great if you get a video for even and odd functions too.. please...

[johnbrennan]

Wonderful presentation as usual---- a pleasure to watch.

[esm-world]

Also please start class 12 math course

[RahulKumar-stys]

I was also waiting a lot for a long time, to hear mam's voice.
And hey! Calculus is back,
Might be this time they will answer our questions of calculus with which they left us. I am very interested!
Thx a lot don't memorise.
Let me make you remember some of the topics you promised us to teach us:-
1. By which angle a stone should be thrown to cover maximum distance. ( CALCULUS)
2.Finding surface areas and volumes using calculus. (CALCULUS)
3. Using imaginary numbers in real life(IMAGINARY NUMBERS).

And please add one from me:-
How to know the equation of function, by knowing its graph to find the area of any irregular shape.
I trust don't memorise that they will surely fulfill their promises.

3.

[namanjain]

The answer is no. as there is just a hole but it isn't defined at that point thus -1 is not in the domain

[abheshsankhe]

No it isn’t at x=1, since I will have to lift my pen first of all. Secondly, it’s value is not defined, but Left hand limit = Right hand limit, so it is a ‘Missing Point Discontinuity’

[Enterprises-zh]

Please start for 11 th students physics chemistry and maths for IIT jee I hope you can do it that

[rushbhai-]

It is discontinuity at -1 because limit exists but f(x) doesnot equal to f(a)
Mam
If its true just say I mean reply me
Or if it is false just say what is the mistake
I mean how is it false
And what is true solution