Tensile Test

Basic principle and practical procedure of the tensile test on ductile metallic materials
- Testing machine (Inspekt 200 kN, Hegewald & Peschke Meß- und Prüftechnik GmbH), specimen, extensometer
- Material with yield point phenomenon
- Elastic and plastic behaviour, uniform elongation, necking, fracture
- Yield strength, tensile strength, percentage elongation at fracture
- Material without yield point phenomenon
- Plastic behaviour, proof strength
Responsible for this video: Prof. Dr.-Ing. Rainer Schwab, Hochschule Karlsruhe (Karlsruhe University of Applied Sciences), Germany

[abdelrahmanhazemmohamedkam]

It''s very interesting to see how things work practically instead of just reading it from books.

[emkox]

No idea why this was in my recommendations, but I watched it and it was interesting. Props for Anneke Reinsperger for speaking English without even the hint of a German accent.

[lucarutigliano]

I'm studying for the metallurgy exam at university and this video helps a lot to visualize and really understand how the complete process works.

[jessiezhao]

I dont work in material science just needed to learn something for work so I landed on your video. Not only the content of the video is informative but I also find how the entire process is explained is very neat! Thank you for sharing!

[maclinacarvalho]

This proved to be very helpful in my engineering practical exams .
🙏🏻

[thenozar]

Never quite understood why we always had two different graphs but thanks to this video it's very clear. Great stuff

[sebastiancrawford]

this is the best video on tensile testing and strain on YouTube

[MaterialsScience]

Mechanical stress sigma is always defined as Force F divided by cross sectional area S (or area A). Or more precise: NOMINAL stress sigma equals force F divided by ORIGINAL cross sectional area S zero.
In the video TWO physical quantities are plotted on the vertical axis: Force F on the right side and stress sigma on the left side. Sorry for this, it may be confusing. You get sigma on the left side by simply taking F and dividing it by the original cross sectional area S zero.

[MaterialsScience]

"Why does the machine not apply any additional force in the 'luda' (Lüder) area of the curve?": This is an important question, and a research topic of mine, please see our publ. "On the nature of the yield point phenomenon" in Acta Materialia. "And why does the machine apply less and less force right before final fracture?" This is due to "material instability": Here the strain hardening effect is not strong enough to compensate the strength decrease due to the decrease in cross sectional area.

[zach]

This is extremely fascinating. I'm super motivated to finish my remaining education. Working two full time jobs for school has been very tiresome.

[osvaldosolis]

This essay is great because it exemplifies that not all materials work in the same way.

[anzebeton]

I'm a sample machinist for the local steel mill and this is exactly what I machine every day.

[RightInstrumentCoLtd]

What happy as same the company in your industry, I am a China company, good video!

[alirio]

This is an insteresting and informative video. I'm a Mechanical Engineering and this information clarifies some concepts.

[stephaniefields]

I’m in 6th grade and this was the first advanced thing I’ve learned like this so thx

[MaterialsScience]

The term "elongation" in ASTM 615 indeed is not specified clearly. To my knowledge it can only mean "percentage elongation after fracture". So one has to put the fragments together and then determine the percentage plastic deformation after fracture has occurred.

[MaterialsScience]

In materials of medium or low ductility, the fracture may take place anywhere along the prismatic part of the specimen, mostly at a weak point. In very ductile materials, the fracture tends to form in the middle region, because there is a certain influence of the grip regions.

[hugoorellan]

It is interesting to see how steel can deform under load applications in a test. Thank you for made it

[AbarajithanGnaneswaran]

Please explain to me this. We are increasing the force gradually and observing the extension, right? Then how can the force reduce in the diagram?

Now I see: the machine is not increasing the force gradually. But, the length is increased continuously and the force needed is plotted in the graph.

[XavierRogers-yt]

This video is really well made, thank you for making it. Finally some really good videos on materials testing. Thanks!!.