Subgroups of S3 and some problems - Chapter 4 - Lecture 6

In this video we use Lagrange's theorem along with NAS condition for a finite subset of a group to be a subgroup of the group to find all subgroups of S3 - the group of permutations on a set containing 3 elements. We also prove that there are four elements in S3 whose square is the identity and 3 elements whose cube is identity. Further since S3 is non abelian, we find two elements x and y in S3 for which (xy)^2 is not equal to x^2y^2.

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[pmabdullah]

Thanks allot mam it is so understanding