Abstract Algebra | If D is a UFD then D[x] is a UFD.

preview_player
Показать описание
We prove an important result that states the ring of polynomials whose coefficients are from a unique factorization domain is itself a unique factorization domain. Along the way, we define the content of a polynomial, prove Gauss' lemma, and prove that if a polynomial factors over the field of fractions of an integral domain, then it also factors over the integral domain itself.

Рекомендации по теме
Комментарии
Автор

Loving these abstract algebra videos. It's easily my favorite subject in higher math

DarkMonolth
Автор

My God. I had forgotten how much I loved higher algebra. I'm so rusty it's embarrassing, but this was very enjoyable to watch.

thehappyapy
Автор

Hi for the exercice Olympide Romania. P a prime a0=p and an+1 = 2 an _ 1. We can find easialy an . If we considere vn = an -1 . Vn is a geometric sequence with 2 ‘ raison’ and p-1 first terme so vn = 2^n *( p-1) then an = 2^n *(p-1) +1 and then everyting will be easy

ikramefa
Автор

Can anyone plzz explain what is content of a primitive polynomial

rupaliyadav
Автор

Thank you! Could you please make a video about Hopf Algebras? I’ve noticed that Youtube lacks videos about it, except for lectures and daunting conferences.

MsSlash
Автор

Great video as always! I'm curious if you're ever planning on doing a video giving an introduction to some of the ideas in your research. The definition of VOAs seems pretty daunting, so it'd be interesting to see how you'd approach it.

randomtiling
Автор

Doesn’t the second Lemma imply Gauss’ Lemma?

s.chitratta
Автор

I wish you can make some videos on combinatorial problems

bttfish
Автор

sir can you please help me out solve 2^x+3^y=72
2^y+3^y=108

maxamedmuuse