ArrayLists (Exercise 1)

Java Programming: Solved Programming Question on ArrayLists in Java
Topics Discussed:
1) Creating a list of unique elements taken from the user, then sorting and printing these elements using an ArrayList in Java.

Music:
Axol x Alex Skrindo - You [NCS Release]

#JavaByNeso #JavaProgramming #ArraysInJava #ArrayLists

[sahil]

ArrayList<String> str = new ArrayList<String>();

System.out.println("Please enter 5 Strings:");

for(int i = 0; i < 5; i++) {
String temp = scr.next();
if(!str.contains(temp)) {
str.add(temp);
}
}

Collections.sort(str);

System.out.println(str);

[jaferalmoalem]

I love u, you have been helping me a lot !

[jamesmoran]

Collections was getting an error for me on Collections.sort(integers); didn't work in BlueJay, it was saying undeclared variable?

[tudorgorea]

3:44 I forgot that there is a function for this, so I wrote this code (it does the same thing):

for(i=1; i<=n; i++) {
System.out.print("x" + i + " = ");
x = ip.nextInt();

ok=1;
for(j=0; j<lista.size(); j++)
if(lista.get(j) == x)
= 0;

if(ok == 1)
lista.add(x);
}

[mayankverma]

Sir plzzzz tell when u will complete full course... Plz answer if u have paid complete tutorials then also we are ready to buy... But plz tell when u will upload full java vedioes

[boooost]

Didn't know I can use integers.contains! Hahaha I had a hard time but managed to solve it anyways.
1. I added ALL the inputs of the user to the ArrayList
2. I sorted the ArrayList
3. I removed every integer that has a duplicate integer in the ArrayList
***
for(int i = 0; i < integers.size(); i++){
for(int j = (i+1); j < integers.size(); j++){
if(integers.get(i) == integers.get(j)){
integers.remove(j);
j--;
}
}
}

Thank you Neso Academy I learned a lot from you guys already. Keep making videos!

[jejewite]

For Strings:

import java.util.ArrayList;
import java.util.Collections;
import java.util.Scanner;

class Test4 {
public static void main(String[] args) throws IndexOutOfBoundsException{
Scanner scanner = new Scanner(System.in);
ArrayList<String> stringsFromUser = new ArrayList<>();
int numberOfStrings = 0;
String temp = null;

System.out.println("How many Strings do you want to enter?");
numberOfStrings = scanner.nextInt();
scanner.nextLine();

for (int n = 1; n <= numberOfStrings; n++){
System.out.println("Enter string number " + n);

}



for (int n = 0; n < stringsFromUser.size() - 1 ; n++){
temp = new
if (temp.equals(new {
stringsFromUser.remove(n + 1);
n--;
}
}
numberOfStrings = 1;
for (String s : stringsFromUser)
+ ")" + s);
}
}

[marcinnalborczyk]

Why does prints out the elements of the array instead of its address like it was in previous videos when we had to use Arrays.toString()?

[suswithcherry]

import java.util.*;

class Check {

public static void main(String[] args) {

Scanner input = new Scanner(System.in);

ArrayList<Integer> numbers = new ArrayList<>();

System.out.print("Enter 5 Integers: ");

for(int i = 0; i < 5; i++) {
int n = input.nextInt();

if(!numbers.contains(n))
numbers.add(n);
}

Collections.sort(numbers);
System.out.println(numbers);

}
}

[bhargavsai]

import java.util.*;
class HelloWorld {
public static void main(String[] args) {
ArrayList<Integer> list=new ArrayList<>();
Scanner s=new Scanner(System.in);
System.out.println("enter five numbers : ");
for(int i=0;i<5;i++){
list.add(s.nextInt());
}
for(int i=0;i<list.size();i++){
int temp=list.get(i);
for(int j=i+1;j<list.size();j++){
if(temp==list.get(j))
list.remove(j);
}
}
Collections.sort(list);
System.out.println(list);
}
}

[-MustakimMusa]

import java.util.ArrayList;
import java.util.Collections;
import java.util.Scanner;
class HelloWorld {
public static void main(String[] args) {
ArrayList<Integer> arr = new ArrayList<>();
System.out.println("Try programiz.proenter 5intss : ");
Scanner my = new Scanner(System.in);
for(int i=0;i<5;i++){
int temp = my.nextInt();
if (!arr.contains(temp))
arr.add(temp);
}
Collections.sort(arr);
System.out.println(arr);
}
}