JavaScript ES6 / ES2015 - [07] Default Params & Spread Operator

Lets take a look at how to use default parameters in ES6. We will also look at the spread operator

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[Chrisdraws]

yeah this is a bad example of the spread operator. It doesn't matter if you do the .apply(null, args) or not, if you do the console log and call the variable it's scope is applied and it is used in the function either way. And it's just does a normal console.log. I would consider reshooting this video with a better example. I've enjoyed all your other videos, they have been very informative and simple.

[braulioandre]

Brad I think what you could to do there is:
function test(){
console.log([...args1, ...args2])
}
test() so both arrays could be merged into one, cause in the example you showed even if you don't use the spread operator we still get the same result. It doesn't have an effect. And since we're using the global variables we don't need to pass them into the function anymore.

[carthago_delenda_est]

Hello. I have one question: why you use $ symbol in paramenters of function?

[manueljordan]

Why in 0:28 the parameter name is declared with '$'?

[dew_reddit]

One important thing when discussing spread operator is that they keep the original data structure immutable which is awesome if you are using frameworks like react(+redux) where application state must be immutable. You also get a lot cleaner and readable code as a bonus (something which is impossible to achieve with all heavily bloated modern frameworks)

[stevemaniar]

@Traversy Media, you can eliminate "function ()" and replace it with just
greet = (greeting="Hello world") => console.log(greeting)
i think its better way to write ES6 way

[TT-udgf]

So the function uses the global variables, there is no need to pass them into the function. I'm confused!

[FauzulChowdhury]

@brad can you please clarify this video in a better way. I think console logging and just calling test() does it already. Why am I using ... For?

[iceman]

The code works without using the spread operator. Does not gives clarity as to why to use the spread operator. Thanks

[stefanage]

At 4:21 I got the same result without using the ... when calling test. ea: test(args1, args2); - printed 1, 2, 3, 4, 5, 6.

[goretushar]

let arg = [1, 2, 3]
function checkTheFunction() {
console.log(arg)
}


function myFunc(value) {
console.log(value)
}
checkTheFunction.apply(arg) // [1, 2, 3]
checkTheFunction(...arg) // [1, 2, 3]
myFunc(...arg) // 1
myFunc(arg) // [1, 2, 3]


Please explain, How it works ?

[AliAkbar-vote]

The pirple node.js course I have got it for free. This ad sucked me up.

[arifsultan]

bad example !! speard operator has no effect at all in your example. Please remove this video and reshoot with better example.

[AliAkbar-vote]

For the first time, I found your mistakes. You should reconsider making a video on spread operator and rest operator. I respect your knowledge sir. Human does mistakes. Please, remove this video and make a right one on this topic. Otherwise people will leave your channel.